I'd like to write an expression with several vectors:
$\vec{t} + \vec{a}$
I'd like the arrow to appear at the same level, but the t arrow appears higher than the a arrow. I tried with \overrightarrow but it's the same problem.
2 Answers
You can also do the following to avoid having to change any of the existing mathematical code.
\documentclass[border=5mm]{standalone}
\let\nvec\vec
\def\vec#1{\nvec{\vphantom t\smash{#1}}}
\begin{document}
$\vec{t} + \vec{a}$
\end{document}
You will have to modify the \def command for the 'tallest' variable used.
answered Jun 17, 2015 at 16:22
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I wonder if it is possible to do some
.aux-file monkeying that will record every argument to which an\alignedvecis applied, calculate the tallest among them, and then use that on the next pass as the height of a strut (to replace the guessing / fiddling required for the\vphantom).– LSpiceJun 17, 2015 at 19:43 -
@LSpice I suspect it would be possible, but probably overkill. If all the vectors are lower case then depending upon the font one of the letters
b, d, f, h, k, l, or twould be the tallest if not the same height. (Sotis a great general choice. If you are using uppercase as vector thenIwould be a good choice for the tallest. Jun 17, 2015 at 19:55 -
I personally ended up using
lwhich is bit higher thant(I used only lowercase vector)– gwenzekJun 18, 2015 at 8:24
Make a new macro for making vectors, say
\newcommand\myvec[1]{\vec{\vphantom{t}#1}}
\vec{\vphantom t\smash{#1}}should work.