# Variadic arguments macro

I am trying to make macro with variadic arguments, iterating over them. The final result is supposed to be:

\foreach[x]((var = \x )){foo}{bar}{baz}\null


evals to

var = foo var = bar var = baz


My naive guess is this one:

\def\Macro#1{\if \null#1 . \else ,\noexpand\Macro \fi}
\Macro foogg\null


I expected it to eval to ,,,,,., but it evals to ,oogg. Am I understanding \noexpand behavior wrong?

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Can you please clarify your aim? However, the test \if\null#1 will always evaluate to false, because \if expands tokens and the expansion of \null is \hbox{}, so \if is comparing \hbox to {. –  egreg Mar 2 '13 at 16:54
Many list parsers (like pgffor and etoolbox) would be able to assist in your task. See Cunning (La)TeX tricks, for example. –  Werner Mar 2 '13 at 17:26

Change \noexpand to \expandafter, that's what you need to "skip" that \fi. As well, as egreg points out, \if\null won't work. Either use \ifx, or change \null to \relax and hope it is not contained in your text. The reason why \relax will work is that it is unexpandable and \if takes it, instead of expanding. For the reason that \relax or \null might be used by someone else, a much safer option is to use a command that doesn't exist, like \thisIStoheczSdelimiter:

\def\Macro#1{\ifx\thisIStoheczSdelimiter#1 . \else ,\expandafter\Macro \fi}
\Macro foogg\thisIStoheczSdelimiter


As for working foreach cycles, look into pgffor package. Your code, IIRC, could be rewritten as

\foreach \x in {foo, bar, baz}{ var = \x, }

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It's not sufficient; see my other comment. –  egreg Mar 2 '13 at 16:56
I know, I missed that it's not \ifx. I'll correct. –  yo' Mar 2 '13 at 16:57
\def\Macro#1{\if \null#1 . \else ,\noexpand\Macro \fi}
\Macro foogg\null

\def\xnull{\null}
\def\Macro#1{\def\tmp{#1}\ifx\tmp\xnull\else ,#1\expandafter\Macro \fi}
\Macro foogg\null

\bye


produces ,foogg from your original then ,f,o,o,g,g from the modified version, in your original the \noexpand makes \Macro act like \relax and so do nothing after the first call, so only f is ever taken as an argument.

The above is plain TeX, but if you are intending this for LaTeX you should really use a different syntax, one of the main aims of LaTeX is to give a unifying syntactic structure, and LaTeX commands never take a variable number of {} arguments. The LaTeX syntax would be a comma separated list within a single {} argument.

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