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I have to draw the following figure. What I have now is uggly. Somehow the structure should be more balanced. Is there a way to do this with tikz-qtree? The point is that it is multiple dominance and furthermore the node lables are not within the tree but next to it. The top node does not have a label.






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That's PSTricks code but the tags are TikZ. Is that on purpose or you just give an example ? – percusse Apr 19 '13 at 12:18
This is just how it is supposed to look like. I started tikz-qtree and I am quite happy with the way it works (without having to name nodes explicitly) but I have no idea how to do this with tikz-qtree or tikz without qtree. – Stefan Müller Apr 19 '13 at 12:39

The best way is to use the library trees like Gonzalo but below I give you the traduction of your code in tikz and after some possibilities without trees with only tikz. The last code is the better attempt.

  \node[anchor=base] at (1,0) {German};
  \node[anchor=base] at (3,0) {Dutch};
  \node[anchor=base] at (5,0) {Danish};
  \node[anchor=base] at (7,0) {English};
  \node[anchor=base] at (9,0) {French};
  \node[anchor=base] at (1.5,2) {SOV};
  \node[anchor=base] at (1.5,1.6) {VC};
  \node[anchor=base] at (3,4) {V2};
  \node[anchor=base] at (7.7,2) {SVO};

  \draw (1,0.4) -- (4,5);
  \draw (2,2) -- (3,0.4);
  \draw (3.4,4) -- (5,0.4);
  \draw (5,0.4) -- (7,2);
  \draw (7,2) -- (7,0.4);
  \draw (4,5) -- (9,0.4);

enter image description here

The last code is better like this:

 \begin{tikzpicture}[every node/.style={anchor=base}]
      (1,0)     node {German}     (3,0)     node {Dutch}
      (5,0)     node {Danish}     (7,0)     node {English}
      (9,0)     node {French}     (1.5,2)   node {SOV}
      (1.5,1.6) node {VC}         (3,4)     node {V2}
      (7.7,2)   node {SVO};

     \draw (1,0.4) -- (4,5)   (2,2) -- (3,0.4)  (3.4,4) -- (5,0.4)
           (5,0.4) -- (7,2)   (7,2) -- (7,0.4)  (4,5) -- (9,0.4);

We can get something like Gonzalo :

\begin{tikzpicture}[every node/.style={anchor=base}]
     (4,5)     coordinate (main)
     (1,0)     node (G) {German}     (3,0)     node (DU) {Dutch}
     (5,0)     node (D) {Danish}     (7,0)     node (E)  {English}
     (9,0)     node (F) {French}     (1.5,2)   node (SO) {SOV}
     (1.5,1.6) node (V) {VC}         (3,4)     node (V2) {V2}
     (7.7,2)   node (S) {SVO};

    \draw (main) -- (V2)  -- (V2) -- (SO)   (main) -- (S) -- (E)
            (V2) -- (D)      (S) -- (F) (S)--(D)  (V) -- (G) (V) -- (DU)  ;

enter image description here

But it's better to not use coordinates, without tree's library the better way is


\begin{tikzpicture}[every node/.style={anchor=base},node distance=2cm and 2cm,on grid]
    \path node (GE) {German}  
          node[right=of  GE]             (DU)  {Dutch}    
          node[right=3cm of  DU]         (DA)  {Danish}
          node[right=of  DA]             (EN)  {English}
          node[right=of  EN]             (FR)  {French}
          node[above=of DU,align=center] (VC)  {SOV\\VC}  
          node[above =of EN]             (SVO) {SVO}
          node[above right=of VC]        (V2)  {V2} 
          coordinate[above right=of V2]  (main)   ; 

    \draw (main) -- (V2) -- (VC) -- (GE)      (main) -- (SVO) -- (DA)
                            (VC)--(DU)                  (SVO) -- (EN) 
                    (V2) -- (DA)                        (SVO) -- (FR) ;

enter image description here

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Thank you very much! This package is so complex and with so many possibilities and it is really great to see it applied to one's own problem. I learned a lot! – Stefan Müller Apr 20 '13 at 9:54

This is one possibility using TikZ; I used the trees library (even though, formally, this isn't a tree):



  level 1/.style={sibling distance=60pt},
  level 3/.style={sibling distance=40pt}
child {node (v2) {V2}
  child {node[text width=2.2em,align=center] {SOV\\VC} 
    child {node {German}} 
    child {node {Dutch}}}
child {
  child {node {SVO} 
    child {node (dan) {Danish}} 
    child {node {English}} 
    child {node {French}}}
\draw (v2) -- (dan);


enter image description here

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