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Consider the code below. In the scope environment, I am using a clip to keep the ellipse between the points. From reading, I know with the let command I can access the coordinates of the points by defining them in the let command \p2 = (P2). Can I access the coordinates to use in the clip?

The goal is so if I change P2, the clip will change too.

  \documentclass[tikz, border=5mm]{standalone}
  \usetikzlibrary{arrows,calc, decorations.markings, intersections}

  \begin{document}

  \begin{tikzpicture}[
    dot/.style = {outer sep = +0pt, inner sep = +0pt, shape = circle, draw = black, label = {#1}},
    small dot/.style = {minimum size = 1pt, dot = {#1}},
    big dot/.style = {minimum size = 2pt, dot = {#1}},
    line join = round, line cap = round, >=triangle 45
    ]
    \node[ fill = black, big dot = {below: \(F\)}] (F) at (0, 0) {};
    \node[ fill = black, big dot = {below: \(P_1\)}] (P1)  at (2, 0) {};
    \node[ fill = black, big dot = {above right=.25cm:\(P_2\)}] (P2) at (-2, 2) {};    

    \begin{pgfinterruptboundingbox}                  
    \begin{scope}[decoration = {markings,
        mark = at position 0.5 with {\arrow{>}}
      }]
      \clip (2, 0) -- (-2, 0) -- (-2, 2.2) -- (2, 2.2) -- cycle;
      \draw[name path global = ellp, postaction = decorate] let
        \p0 = ($(P2) - (F)$),
        \p1 = ($(P1) - (P2)$)
      in (P2|-P1) ++ (\x1, 0) arc (0:100: \x1 and \y0);                                         
  \end{scope}
\end{pgfinterruptboundingbox}

\path[name path = aux1] (P2) circle [radius = 1bp];
\draw[name intersections = {of = ellp and aux1}, -latex] (P2) --
($(intersection-2)!.75cm!(intersection-1)$);
\draw [-latex] (P2) --
($(P2)!0.75cm!-90:($(intersection-2)!.75cm!(intersection-1)$)$);


  \end{tikzpicture}
  \end{document} 
share|improve this question
    
What do you mean? You can use (\p2) as well as \x2 and \y2 (in the canvas) after you add \p2 = (P2), though I would add this first, so that you can use \p2 in the calculation of the other nodes, too. — Or do you mean something like \clip (P1) rectangle (P2);? –  Qrrbrbirlbel Jun 23 '13 at 21:27
    
@Qrrbrbirlbel so I can just go into the clip coordinates and add \x2 and \y2 as is? –  dustin Jun 23 '13 at 21:30
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1 Answer

up vote 1 down vote accepted

Answering directly your question: yes, you can use the let..in syntax as part of a \clip command. For example:

\clip let \p1=(P2) in (\x1,\y1) rectangle (P1);

This will allow you to do some arithmetic on the individual x and y coordinates, but you have a drawback: you need to specify the units of the constants you add or substract, as for example:

\clip let \p1=(P2) in (\x1 + 0.5cm, \y1) rectangle (P1);

if you don't specify the units, tikz will use pt as the default. And since points are very small, you won't see any change simply with \x1+0.5.

Specifying the units is not optimal, since it will make the figure not easily scalable. If you give the option x=5mm, for example, all dimensionless coordinates will be halved, but your 0.5cm constant will not.

A better solution is to use calc expressions, as in:

\clip ($(P2)+(0.5, 0)$) rectangle (P1);

this not only has a clearer syntax, but also works without specifying the dimensions of the (0.5, 0) constant, and thus makes the image easily scalable. Note that to use these kind of expressions \usetikzlibrary{calc} is required (but you had it anyway).

share|improve this answer
    
Well, whether it is a better solution to use calc expressions I’ll leave that undecided. But it is certainly better to use the rectangle path operator here. Without calc, you can also do \clip [shift=(right:.5)] P2) rectangle (P1); or {(.5,0)} of course. (This is also true for the second code snipped so you don’t need to specify the unit for the 0.5cm part making it flexible to changes in the coordinate system.) –  Qrrbrbirlbel Jun 24 '13 at 21:24
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