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I tried to fix this problem by reading the answers to the questions on this forum related to this topic, but I did not find any solution. Could you help me, please? The thing is that I have to break a long equation with an initial bracket...Because of that, I am not able to use neither split nor align...Here the text

u_{i}^{n+1} = \frac{1}{2} \hat u_m^n e^{Ii\phi_m} \left\{ \frac{1}{2} \left(e^{I\phi_m}+e^{-I\phi_m}+2\right) 
-\frac{\Gamma}{2} \left(e^{I\phi_m} + e^{-I\phi_m}\right) - \Gamma \left[ \frac{1}{2} \left(e^{I\phi_m} + e^{-I\phi_m}\right) - \frac{\Gamma}{2} \left(e^{I\phi_m} + e^{-I\phi_m} -2\right)\right] \right\}. \notag
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marked as duplicate by Peter Jansson, Jubobs, cmhughes, barbara beeton, Guido Jan 30 at 19:34

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

Possible duplicate: Left/Right across multiline equation –  Werner Jan 30 at 17:51
The (easiest) suggested solution in this case is to use \big-style delimiters... –  Werner Jan 30 at 17:51
ie write \bigl\{ instead of \left\{ and \bigr\} instead of \right\}. Then you can put it in a split. –  Thruston Jan 30 at 17:53

1 Answer 1

It seems that the terms in your equation have the same height. This means that TeX can estimate the braces height from any of them. Therefore the construction

 \left\{ ....  \right.\\
 \left.  ....  \right\}

works right (otherwise we would need to put the delimiter sizes explicitly or to use \vphantom{THE_HIGHEST_TERM} in the corresponding line).

This works:


u_{i}^{n+1} = \frac{1}{2} \hat u_m^n e^{Ii\phi_m} \left\{ \frac{1}{2}
  -\frac{\Gamma}{2} \left(e^{I\phi_m} + e^{-I\phi_m}\right) - 
   \Gamma \left[ \frac{1}{2} \left(e^{I\phi_m} + e^{-I\phi_m}\right) -
   \frac{\Gamma}{2} \left(e^{I\phi_m} + e^{-I\phi_m} -2\right)\right]
\right\}. \notag 


enter image description here

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