# Tikz : texture cube faces using png image

I would like to draw a cube using Tikz with some faces of the cube having a texture on it (texture would be a PNG image)

my current code is at follows :

\documentclass{standalone}
\usepackage{tikz}
\usetikzlibrary{3d,calc}
\tikzset{persp/.style={scale=3.0,x={(-0.8cm,-0.4cm)},y={(0.8cm,-0.4cm)}, z={(0cm,1cm)}},points/.style={fill=white,draw=black,thick}}

\begin{document}
\begin{tikzpicture}[persp]\def\i{-15}
\pgfmathparse{cos(\i)}\let\ci\pgfmathresult
\pgfmathparse{sin(\i)}\let\si\pgfmathresult
\coordinate (Ocube) at (0,0,0);
\coordinate (Xcube) at (\ci,\si,0);
\coordinate (Ycube) at (-\si,\ci,0);
\coordinate (Zcube) at (0,0,1);
\coordinate (C0) at ($(Ocube)-(Xcube)-(Ycube)-(Zcube)$);
\coordinate (C1) at ($(Ocube)+(Xcube)-(Ycube)-(Zcube)$);
\coordinate (C2) at ($(Ocube)-(Xcube)+(Ycube)-(Zcube)$);
\coordinate (C3) at ($(Ocube)+(Xcube)+(Ycube)-(Zcube)$);
\coordinate (C4) at ($(Ocube)-(Xcube)-(Ycube)+(Zcube)$);
\coordinate (C5) at ($(Ocube)+(Xcube)-(Ycube)+(Zcube)$);
\coordinate (C6) at ($(Ocube)-(Xcube)+(Ycube)+(Zcube)$);
\coordinate (C7) at ($(Ocube)+(Xcube)+(Ycube)+(Zcube)$);
\fill[black!20, draw=black, dashed,opacity=0.3] (C0)--(C1)--(C3)--(C2)--cycle;
\fill[black!20, draw=black, dashed,opacity=0.3] (C0)--(C1)--(C5)--(C4)--cycle;
\fill[black!20, draw=black, dashed,opacity=0.3] (C0)--(C2)--(C6)--(C4)--cycle;
\fill[black!20, draw=black, thick,opacity=0.3] (C4)--(C5)--(C7)--(C6)--cycle;
\fill[black!20, draw=black, thick,opacity=0.3] (C2)--(C3)--(C7)--(C6)--cycle;
\fill[black!20, draw=black, thick,opacity=0.3] (C1)--(C3)--(C7)--(C5)--cycle;
\coordinate (Q0) at ($(Ocube)-.8*(Xcube)+(Ycube)-.8*(Zcube)$);
\coordinate (Q1) at ($(Ocube)+.8*(Xcube)+(Ycube)-.8*(Zcube)$);
\coordinate (Q2) at ($(Ocube)-.8*(Xcube)+(Ycube)+.8*(Zcube)$);
\coordinate (Q3) at ($(Ocube)+.8*(Xcube)+(Ycube)+.8*(Zcube)$);
\fill[white!20, draw=black, thick,opacity=0.3] (Q0)--(Q1)--(Q3)--(Q2)--cycle;
\end{tikzpicture}
\end{document}


On the last line, rather then filling white a color (white!20), I would like to draw the image "face.png". This drawing must be distorded so to fit the face realisticaly.

Could someone help me doing that ?

-
Welcome to TeX.SX! Please make your code compilable (if possible), or at least complete it with \documentclass{...}, the required \usepackage's, \begin{document}, and \end{document}. That may seem tedious to you, but think of the extra work it represents for TeX.SX users willing to give you a hand. Help them help you: remove that one hurdle between you and a solution to your problem. – Jubobs Mar 25 '14 at 11:17
I juste edited my code, sorry – Amxx Mar 25 '14 at 11:27

Not exactly an answer to the question, but it is fun.

\documentclass{standalone}
\usepackage{tikz}
\usetikzlibrary{backgrounds}

\begin{document}
\begin{tikzpicture}
\draw[yellow,yslant=0.5] (0,0) rectangle (2,2);
\node[yslant=0.5,anchor=center,opacity=0.3]  at (1,1.5) {\includegraphics[width=2cm,height=2cm]{example-image-a}};
\draw[magenta,yslant=-0.5] (-2,2) rectangle (0,0);
\node[yslant=-0.5,anchor=center,opacity=0.3]  at (-1,1.5) {\includegraphics[width=2cm,height=2cm]{example-image-b}};
\begin{scope}[on background layer]
\draw[orange,yslant=-0.5] (0,2) rectangle (2,4);
\node[yslant=-0.5,anchor=center,xshift=0cm,yshift=1cm,opacity=0.3]  at (1,1.5) {\includegraphics[width=2cm,height=2cm]{example-image-b}};
\draw[green,yslant=0.5,,xshift=-2cm,yshift=2cm] (0,0) rectangle (2,2);
\node[yslant=0.5,anchor=center,xshift=-2cm,yshift=2cm,opacity=0.3]  at (1,1.5) {\includegraphics[width=2cm,height=2cm]{example-image-a}};
\draw[blue,yslant=-0.5,xslant=1] (-2,0) rectangle (0,2);
\node[yslant=-0.5,anchor=center,xshift=0cm,yshift=2cm,xslant=1,opacity=0.3]  at (-0,-1) {\includegraphics[width=2cm,height=2cm]{example-image-a}};
\end{scope}
\draw[red,yslant=-0.5,xslant=1] (-4,2) rectangle (-2,4);
\node[yslant=-0.5,anchor=center,xshift=0cm,yshift=4cm,xslant=1,opacity=0.3]  at (-0,-1) {\includegraphics[width=2cm,height=2cm]{example-image-a}};

\end{tikzpicture}
\end{document}


-
Some explanation text would have been welcom but I manage to make it work. However, I had to manualy tweak yslant, and it's therefore not a good solution in as it doesnt adapt to my a variable based projection. – Amxx Mar 25 '14 at 16:04
@Amxx That is why it is not an exact answer :) But this was the easiest. – Harish Kumar Mar 25 '14 at 22:55

There are several questions on the site which address filling a shape with an image in TikZ, for example:

We can adapt those solutions to your 3D shape. We use \clip to restrict to the front square of the cube, then add the image, and finally we draw the border around it.

I’ve replaced the line:

\fill[white!20, draw=black, thick,opacity=0.3] (Q0)--(Q1)--(Q3)--(Q2)--cycle;


with

\def\frontsquare{(Q0)--(Q1)--(Q3)--(Q2)--cycle}

\begin{scope}
\clip \frontsquare;
\node {\includegraphics{grass.jpg}};
\end{scope}

\draw[black, thick] \frontsquare;


First I define \frontsquare to the area you want to fill. The \clip contained in the scope restricts everything else we draw to within that area, until \end{scope}. When I use \includegraphics to add an image, only the part of the image that is within the front square. The \draw command then adds a border.

This is what the resulting cube looks like:

and here’s the complete code:

\documentclass{standalone}
\usepackage{tikz}
\usetikzlibrary{3d,calc}
\tikzset{persp/.style={scale=3.0,x={(-0.8cm,-0.4cm)},y={(0.8cm,-0.4cm)}, z={(0cm,1cm)}},points/.style={fill=white,draw=black,thick}}

\begin{document}
\begin{tikzpicture}[persp]\def\i{-15}
\pgfmathparse{cos(\i)}\let\ci\pgfmathresult
\pgfmathparse{sin(\i)}\let\si\pgfmathresult
\coordinate (Ocube) at (0,0,0);
\coordinate (Xcube) at (\ci,\si,0);
\coordinate (Ycube) at (-\si,\ci,0);
\coordinate (Zcube) at (0,0,1);
\coordinate (C0) at ($(Ocube)-(Xcube)-(Ycube)-(Zcube)$);
\coordinate (C1) at ($(Ocube)+(Xcube)-(Ycube)-(Zcube)$);
\coordinate (C2) at ($(Ocube)-(Xcube)+(Ycube)-(Zcube)$);
\coordinate (C3) at ($(Ocube)+(Xcube)+(Ycube)-(Zcube)$);
\coordinate (C4) at ($(Ocube)-(Xcube)-(Ycube)+(Zcube)$);
\coordinate (C5) at ($(Ocube)+(Xcube)-(Ycube)+(Zcube)$);
\coordinate (C6) at ($(Ocube)-(Xcube)+(Ycube)+(Zcube)$);
\coordinate (C7) at ($(Ocube)+(Xcube)+(Ycube)+(Zcube)$);
\fill[black!20, draw=black, dashed,opacity=0.3] (C0)--(C1)--(C3)--(C2)--cycle;
\fill[black!20, draw=black, dashed,opacity=0.3] (C0)--(C1)--(C5)--(C4)--cycle;
\fill[black!20, draw=black, dashed,opacity=0.3] (C0)--(C2)--(C6)--(C4)--cycle;
\fill[black!20, draw=black, thick,opacity=0.3] (C4)--(C5)--(C7)--(C6)--cycle;
\fill[black!20, draw=black, thick,opacity=0.3] (C2)--(C3)--(C7)--(C6)--cycle;
\fill[black!20, draw=black, thick,opacity=0.3] (C1)--(C3)--(C7)--(C5)--cycle;
\coordinate (Q0) at ($(Ocube)-.8*(Xcube)+(Ycube)-.8*(Zcube)$);
\coordinate (Q1) at ($(Ocube)+.8*(Xcube)+(Ycube)-.8*(Zcube)$);
\coordinate (Q2) at ($(Ocube)-.8*(Xcube)+(Ycube)+.8*(Zcube)$);
\coordinate (Q3) at ($(Ocube)+.8*(Xcube)+(Ycube)+.8*(Zcube)$);

\def\frontsquare{(Q0)--(Q1)--(Q3)--(Q2)--cycle}

\begin{scope}
\clip \frontsquare;
\node {\includegraphics{grass.jpg}};
\end{scope}

\draw[black, thick] \frontsquare;
\end{tikzpicture}
\end{document}

-
I saw such exemples, but they don't fit my needs as they just clip the image to the polygone. In my case the image is a QRcode and i would like it to fit the square face which means distord it accordingly – Amxx Mar 25 '14 at 12:09
@Amxx: Of course. I’ve picked a bad image: the grass doesn’t show the lack of perspective transform. Playing with the tikz-3dplot library might give a way to fix it, but I can’t think of one off the top of my head. – alexwlchan Mar 25 '14 at 12:12
That's precisely what I'm looking for – Amxx Mar 25 '14 at 13:59