# Slanted greater than and equal to, less than and equal to

Need to produce a "Greater than" or "Equal to" symbol with a slanted equal component of the symbol, i.e. the bottom bar not parallel to the typed line, but parallel to the bottom bar of the right facing arrow. \geq begets a normal "greaterthan"/"equal to"-symbol. I've found on the internet and then tried \geqslant, but it does not work. I get an error message:

! Undefined control sequence.
l.1171 ...frac{k^{n-1}_1}{k} \right) , n \geqslant
1
?

Am I missing something in the preamble?

I assume there is a similar way to achieve a Less than and equal to slant.

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Have a look at “How to look up a symbol?” for ideas how you can easily find a particular symbol. –  Johannes_B Mar 26 at 13:32
Possible duplicate to stackoverflow.com/q/2596921 –  LaRiFaRi Mar 26 at 13:37

You need the amssymb package in order to use the \leqslant and \geqslant symbols.

\documentclass{article}
\usepackage{amssymb}
\begin{document}
$a-b\geqslant 0 \iff a \geqslant b \iff b \leqslant a.$
\end{document}


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Worked like a charm! Thanks. I'll be book marking. –  TommyK Mar 26 at 13:55

There is also \eqslantless and \eqslantgtr from amssymb:

\documentclass{article}
\usepackage{amssymb}
\begin{document}
$a \eqslantless b$ $a \eqslantgtr b$
\end{document}


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WOW! that was fast! Works like a champ. I'm bookmarking this page! –  TommyK Mar 26 at 13:53