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Need to produce a "Greater than" or "Equal to" symbol with a slanted equal component of the symbol, i.e. the bottom bar not parallel to the typed line, but parallel to the bottom bar of the right facing arrow. \geq begets a normal "greaterthan"/"equal to"-symbol. I've found on the internet and then tried \geqslant, but it does not work. I get an error message:

! Undefined control sequence.
l.1171 ...frac{k^{n-1}_1}{k} \right) , n \geqslant

Am I missing something in the preamble?

I assume there is a similar way to achieve a Less than and equal to slant.

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Have a look at “How to look up a symbol?” for ideas how you can easily find a particular symbol. – Johannes_B Mar 26 '14 at 13:32
Possible duplicate to stackoverflow.com/q/2596921 – LaRiFaRi Mar 26 '14 at 13:37
up vote 12 down vote accepted

You need the amssymb package in order to use the \leqslant and \geqslant symbols.

\[ a-b\geqslant 0 \iff a \geqslant b \iff  b \leqslant a.\]

enter image description here

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Worked like a charm! Thanks. I'll be book marking. – TommyK Mar 26 '14 at 13:55

There is also \eqslantless and \eqslantgtr from amssymb:

  $a \eqslantless b$ $a \eqslantgtr b$

enter image description here

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WOW! that was fast! Works like a champ. I'm bookmarking this page! – TommyK Mar 26 '14 at 13:53

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