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Thanks for helping me out.

How can I make the following tree-diagrams?


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See also this related question, Probability tree using TikZ for Bernoulli experiments?. – chl Jun 4 '11 at 19:11

There is a nice example of a probability tree on TeXample.net. That might help you get started.

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Isn't this more of a comment than an answer? – Svend Tveskæg Jun 7 '15 at 8:48
@Svend Well, I though it was an answer (albeit short) but I see no problem if a mod convert it to a comment. – chl Jun 8 '15 at 11:21
I'm not saying that is a comment; I'm just asking. :) – Svend Tveskæg Jun 8 '15 at 12:17

A forest solution though there are better versions around if you search, I think. This is not exactly like the image you linked to because that one seems rather ugly to me. Obviously, you can adjust this if you prefer greater ugliness.

  left marble colour/.store in=\leftmarblecolour,
  right marble colour/.store in=\rightmarblecolour,
  left marble colour=black,
  right marble colour=red,
  probability tree/.style={
    for tree={
      s sep+=2.5mm,
      if n=1{
        before typesetting nodes={
          edge label/.wrap pgfmath arg={node [midway, below, font=\scriptsize, text=black] {##1}}{content()},
        before typesetting nodes={
          edge label/.wrap pgfmath arg={node [midway, above, font=\scriptsize, text=black] {##1}}{content()},
      before packing={
        typeset node,
    for descendants={
      if n=1{make descendant marble=\leftmarblecolour}{make descendant marble=\rightmarblecolour},
    before drawing tree={
      for tree={
        if n children=0{
  marble/.style={circle, minimum width=2.5pt, fill=#1, draw=#1, inner sep=0pt},
  make descendant marble/.style={
    delay n={int(level())}{
      for descendants={
        if n children=0{
          append={[, grow=0, marble=#1, no edge, l+=-10mm]}
  probability tree,
  left marble colour=blue
  [, name=t0 [\nicefrac{3}{5}[\nicefrac{5}{9}][\nicefrac{4}{9}]][\nicefrac{2}{5}, name=t1 [\nicefrac{2}{3}][\nicefrac{1}{3}, name=t2]]]
  \foreach \i/\j/\k/\l [count=\n] in {3/5/5/9,3/5/4/9,2/5/2/3,2/5/1/3}
    \node (l\n) at (n\n) [label={[label distance=2.5mm, inner sep=0pt, , font=\scriptsize]right:$\frac{\i}{\j}.\frac{\k}{\l}$}] {};
  \coordinate [above=7.5mm of t2] (m1);
  \path [draw, fill, font=\scriptsize\itshape] (m1 -| t0) circle (1pt) -- (m1 -| t1) node [midway, below] {first}  circle (1pt) -- (m1 -| t2) node [midway, below] {second}  circle (1pt) -- ([xshift=2.5mm]m1 -| n3) node [midway, below] {result} circle (1pt) -- ++(7.5mm,0) node [midway, below] {\phantom{l}p\phantom{l}} circle (1pt);

probability tree

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