# How to avoid the poles of the voltages to overlap the resistors?

Using this code in circuitkz I get this circuit

 \begin{circuitikz}[american]
\ctikzset {voltage/distance from node=1};
\draw
(0,0) to[battery,l=V] (0,2)
to[R,l^=$R_1$,v=$V_1$] (4,2)
to[R,l=$R_2$,v=$V_2$] (4,0)
(4,0) -- (0,0)
;
\end {circuitikz}


How can I move V1 and V2 labels to the left and down, both the label themselves and the poles? It's so nasty to get the poles overlapping the resistors!!

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Adjust the value of \ctikzset {voltage/distance from node=0.5}, say 0.5 or 0.8.

Code

\documentclass{article}
\usepackage[american,siunitx]{circuitikz}
\begin{document}
\ctikzset {voltage/distance from node=0.5}
\begin{circuitikz}%[american]
\draw
(0,0) to[battery,l=V] (0,2)
to[R,l^=$R_1$,v=$V_1$] (4,2)
to[R,l=$R_2$,v=$V_2$] (4,0)
(4,0) -- (0,0)
;
\end{circuitikz}
\end{document}

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This seems to fix just the poles overlapping. I'd need to displace V labels as well. Thnx. – agrgal May 14 '14 at 6:24
A tricky solution was to define "opens" in the circuit: \begin{circuitikz}[american] \ctikzset {voltage/distance from node=0.8}; \draw (0,0) to[battery,l=V] (0,4) to[R,l^=$R_1$] (6,4) to[R,l=$R_2$] (6,0) (2,3.5) to[open,v=$V_1$] (4,3.5) (5.5,3) to[open,v=$V_2$] (5.5,1) (6,0) -- (0,0) ; \end {circuitikz} – agrgal May 14 '14 at 6:25
Ya, use the open circuit skill with different coordinates, but still need distance from node=0.8, right? Did you try distance from node=1 with the tricky solution? – Jesse May 14 '14 at 6:55
Sorry, you had two follow-ups. As to the first question, here is my solution -- Use of raisebox and hspace skills. For example to[R,l^=$R_1$,v=\raisebox{-20pt}{$V_1$}] (4,2) to[R,l=$R_2$,v=\hspace{-20pt} $V_2$] (4,0). You may need to change the -20pt to suit your needs. Or further reading tex.stackexchange.com/a/161476/34618 – Jesse May 14 '14 at 7:04
both distance from nodeand \raisebox \hspace worked well! Now it looks much better!! Anyway, I noticed poles don't move down \ left as the voltage labels do. They don't seem to be affected by \hspace or \raisebox. Can they move along the voltage labels? – agrgal May 14 '14 at 14:00

A PSTricks solution:

\documentclass{article}

\usepackage{pst-circ}

\begin{document}

\psset{dipolestyle = zigzag}
\begin{pspicture}(-0.8,0)(10.75,6.75)
\pnodes{P}(0,0)(0,6)(4,5.7)(6,5.7)(10,6)(9.7,4)(9.7,2)(10,0)
\battery[labeloffset = -22pt](P1)(P0){$V$}
\resistor[labeloffset = 16pt](P1)(P4){\large $R_{1}$}
\resistor[labeloffset = -17pt](P1)(P4){\large $V_{1}$}
\rput(P2){$+$}
\rput(P3){$-$}
\resistor[labeloffset = 16pt](P4)(P7){\large $R_{2}$}
\resistor[labeloffset = -17pt](P4)(P7){\large $V_{2}$}
\rput(P5){$+$}
\rput(P6){$-$}
\wire(P7)(P0)
\end{pspicture}

\end{document}


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1. No need to reinvent the wheel. Tension label and polarity sign are already provided by the package. 2. The polarity of the battery must be reversed. – kiss my armpit May 13 '14 at 20:53

Reducing the number of keystrokes used in the existing PSTricks answer.

\documentclass[pstricks,border=12pt,12pt]{standalone}
\usepackage{pst-circ}

\psset
{
dipolestyle=zigzag,
labeloffset=.8,
tensionstyle=pm,
tensionoffset=-.8,
tensionlabeloffset=-.8,
}

\begin{document}

\begin{pspicture}(8,6)
\pnodes{P}(1,0)(1,5)(7,5)(7,0)
\vdc[labeloffset=-.8](P1)(P0){$V$}
\resistor[tensionlabel=$V_1$](P1)(P2){$R_1$}
\resistor[tensionlabel=$V_2$](P2)(P3){$R_2$}
\wire(P3)(P0)
\end{pspicture}

\end{document}


## Notes

If you want to use PSTricks rather than TikZ, make sure you compile it with either

• xelatex or

• latex followed by dvips followed by ps2pdf.

At the end, you will get a diagram (in PDF) which you can import from within your main TeX file via \includegraphics and the main TeX file can be compiled with pdflatex.

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Thanks for the answer. Excuse me, I'm newbiw in Latex. So, Must I change package circuitikz by pst-circ? Couldn't I do using circuitikz? – agrgal May 14 '14 at 6:28