TeX - LaTeX Stack Exchange is a question and answer site for users of TeX, LaTeX, ConTeXt, and related typesetting systems. Join them; it only takes a minute:

Sign up
Here's how it works:
  1. Anybody can ask a question
  2. Anybody can answer
  3. The best answers are voted up and rise to the top

How to remove the rectange who surrounds the A character and to draw that char vertically, please ?

\documentclass[]{scrartcl}
\usepackage{tikz}
\usetikzlibrary{fit,calc,positioning,decorations.pathreplacing,matrix}

\begin{document}   

\begin{tikzpicture}[decoration={brace}][scale=2] 
\node [draw] (A) {A}; 
\node [fit=(A)] (fit) {};              
\draw [decorate,line width=1pt] 
  ([yshift=-5pt]fit.south west) -- ([yshift=5pt]fit.north west);
\end{tikzpicture}

\end{document} 

Thanks a lot!

share|improve this question
    
What do you mean by "draw that char vertically,". Do something like \node [scale=2] (A) {A};. – Harish Kumar May 18 '14 at 1:11
    
@HarishKumar, to draw it translated by 90° . – dgs May 18 '14 at 1:16
    
You want to rotate the brace too? – Harish Kumar May 18 '14 at 1:17
    
Don't say draw if you don't want it to draw the node i.e. a box around it. Just say e.g. \node (A) {A};. Do you mean you want the A horizontally? – cfr May 18 '14 at 1:17
up vote 5 down vote accepted

To suppress the rectangle, delete the draw option; to rotate the node contents, use the rotate=<angle> option:

\documentclass[]{scrartcl}
\usepackage{tikz}
\usetikzlibrary{fit,calc,positioning,decorations.pathreplacing,matrix}

\begin{document}   

\begin{tikzpicture}[decoration={brace},scale=2] 
\node [rotate=90] (A) {A}; 
\node [fit=(A)] (fit) {};              
\draw [decorate,line width=1pt] 
  ([yshift=-5pt]fit.south west) -- ([yshift=5pt]fit.north west);
\end{tikzpicture}

\end{document}

enter image description here

As in your other question, it's still not clear to me why you use the fit node and the remarks I made about using two optional arguments and the scale option.

share|improve this answer

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.