# Symbol division latex [duplicate]

I am studying the phasor method for solving electrical circuits. Have tried using tables and researched a lot on the internet but have not found a simple command to represent the numbers a and b in the diagram below:

Thanks for any help.

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## marked as duplicate by Werner, texenthusiast, Mico, Guido, egregJul 31 '14 at 6:47

@Sigur I think this is not a duplicate of the linked question; there, the goal is to effectively calculate the division; here, the OP is interested just in the division-like symbol, but without any calculations. – Gonzalo Medina Jul 31 '14 at 1:33
@GonzaloMedina, I was guided by the title therein How to make the traditional division? – Sigur Jul 31 '14 at 1:54
@GonzaloMedina Voted to reopen but my Guess: Possible Duplicate of In-line long division symbol (French style) – texenthusiast Jul 31 '14 at 4:57

If it is simply a diagram, you can use a tabular.

\documentclass{article}
\newcommand\Phasor[2]{%
\setlength\tabcolsep{2pt}  %% change 2pt suitably
\begin{tabular}{c|c}
#1 & #2 \\\cline{2-2}
\end{tabular}
}
\begin{document}
This is \Phasor{a}{b} well a phasor.
\end{document}


Certainly one can use tikz but, for a change, I would not present one. But if you are interested, that is a different case ;)

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It worked perfectly. Thank you very much! – MathFacts Jul 31 '14 at 0:58

In phasors, the electrical quantities are represented by a magnitude and an angle. The symbol for the angle is not the same as the inline traditional division symbol, but \angle is used in math mode for this.

For example for an R-L circuit with V and I can be expressed as follows:

\documentclass[12pt,a4paper]{article}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\begin{document}
\begin{aligned} V_{sm} &= V_m \angle \phi,\quad \textup{and}\\ I_m &= I_m \angle \theta \end{aligned}
\end{document}


For more complex formulae one should go with the Steinmetz package as pointed out in the comment of egreg. Here is an example:

\documentclass{article}
\usepackage{steinmetz}
\begin{document}
\begin{itemize}
\item Inductor, $L$: $\mathbf{Z}=j\omega L=\omega L\phase{90^{\circ}}$,
\item Capacitor, $C$: $\displaystyle\mathbf{Z}=\frac{1}{j\omega C}=-j\frac{1}{\omega C}=\frac{1}{\omega C}\phase{-90^{\circ}}$.
\item  $\mathbf{Z}= \phase{\alpha+\beta}$
\end{itemize}
\end{document}


The output is:

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The steinmetz package has been thought for this application. – egreg Jul 31 '14 at 6:47
I have updated my answer accordingly, thanks – AboAmmar Jul 31 '14 at 15:30