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I think you get what I am trying to do, but I dont know how to align the equal signs the entire way down and still have the vertical ellipses.

Assume $\displaystyle \sum_{i=1}^{n}\alpha _{i}^{i}=\sum_{i=1}^{n}\beta _{i}^{i}$ for $j=1,\ldots,k-1$.  By definition,
\alpha_{1}+\alpha_{2}+\ldots+\alpha_{n} &= \beta_{1}+\beta_{2}+\ldots+\beta_{n}\\ 
\alpha_{1}^2+\alpha_{2}^2+\ldots+\alpha_{n}^2 &= \beta_{1}^2+\beta_{2}^2+\ldots+\beta_{n}^2\\
\vdots+\vdots+\ldots+\vdots &= \vdots+\vdots+\ldots+\vdots\\
\alpha_{1}^{k-1}+\alpha_{2}^{k-1}+\ldots+\alpha_{n}^{k-1}&= \beta_{1}^{k-1}+\beta_{2}^{k-1}+\ldots+\beta_{n}^{k-1}
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Thank you for getting back to me. Both answers are very helpful. – J Gutierrez Jul 3 '11 at 19:38

I recommend using an alignatenvironment for aligning at equal signs and at the plus signs. You could use \ or \quad etc. around \vdots or align them as well.

An example, perhaps using more & than necessary:

\alpha_{1}&+\alpha_{2}&&+\ldots&&+\alpha_{n} &&= \beta_{1}&&+\beta_{2}&&+\ldots+\beta_{n}\\ 
\alpha_{1}^2&+\alpha_{2}^2&&+\ldots&&+\alpha_{n}^2 &&= \beta_{1}^2&&+\beta_{2}^2&&+\ldots+\beta_{n}^2\\
\vdots\ &+\ \vdots&&+\ldots&&+\ \vdots &&= \ \vdots&&+\ \vdots&&+\ldots+\ \vdots


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\xalpha{1}{}+\xalpha{2}{}+\ldots+\xalpha{n}{} =
\xalpha{1}{2}+\xalpha{2}{2}+\ldots+\xalpha{n}{2} =
\xalpha[\lvdots]{}{}+\xalpha[\lvdots]{}{}+\ldots+\xalpha[\lvdots]{}{} =
\xalpha{1}{k-1}+\xalpha{2}{k-1}+\ldots+\xalpha{n}{k-1} =

I've made all summands of the same width via \xalpha and \xbeta, centering the actual summand in a box as wide as \alpha^{k-1} or \beta^{k-1}. The \vdots need to be lowered a bit.

One might use a more sophisticated macro, by taking into account that all half lines are of the same type.

enter image description here

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