# What is command of doubled \measuredangle?

What is command of \measuredangle doubled?

Thanks

-
There is no such predefined symbol available, I'm afraid. – egreg Feb 20 at 9:41
If there is some standard usage for this symbol can you please provide a reference -- just curious. – Peter Grill Feb 20 at 11:45
echoing @PeterGrill's comment, if there is a standard usage and a reference (in a published source), i will be happy to submit it to unicode. – barbara beeton Feb 20 at 16:48
@ Peter Grill , @ barbara beeton yes it is exists in a geometry book that i am typing now. – Hadi Safi aghdam Feb 21 at 10:24

There's no predefined symbol, as far as I know; you can get a decent emulation with picture mode. It's not really good at scriptscript size, but I don't think you'll need it at such level.

\documentclass{article}
\usepackage{pict2e}
\usepackage{amssymb}

\makeatletter
\DeclareRobustCommand{\measuredangledouble}{%
\mathord{\mathpalette\@measangdbl\relax}%
}

\newcommand{\@measangdbl}[2]{%
\sbox\z@{$\m@th#1\measuredangle$}%
\setlength\unitlength{\wd\z@}%
\ifx#1\displaystyle
\def\@mangle{50}\def\@mratio{0.96}%
\fi
\ifx#1\textstyle
\def\@mangle{50}\def\@mratio{0.96}%
\fi
\ifx#1\scriptstyle
\def\@mangle{42}\def\@mratio{0.83}%
\fi
\ifx#1\scriptscriptstyle
\def\@mangle{36}\def\@mratio{0.67}%
\fi
\begin{picture}(1,\@mratio)
\roundcap\roundjoin\linethickness{0.06\unitlength}
\polyline(0.9,\@mratio)(0.1,0.03)(0.9,0.03)
\put(0.1,0.03){\arc[-3,\@mangle]{0.4}}
\put(0.1,0.03){\arc[-3,\@mangle]{0.55}}
\end{picture}%
}
\makeatother

\begin{document}
$\measuredangle\measuredangledouble$

$\scriptstyle\measuredangle\measuredangledouble$

$\scriptscriptstyle\measuredangle\measuredangledouble$

\end{document}


-

Deleted since apparently not useful ...

Here's a TikZ version, not perfect so far.

\documentclass{article}
\usepackage{amssymb}
\usepackage{mathtools}

\newsavebox{\tempboxa}
\newcommand{\doubledmeasuredangle}[1][.]{%  Note: '.' is a placeholder for the current color.
\savebox{\tempboxa}{$\measuredangle$}%
\resizebox{\wd\tempboxa}{\ht\tempboxa}{%
\begin{tikzpicture}[line width=1.5,#1]
\draw (1,0) coordinate (A) -- (0,0) coordinate (B)
-- (1,1) coordinate (C)
pic [draw,line width=1.5,angle radius=0.5cm] {angle = A--B--C}
pic [draw,line width=1.5,angle radius=0.25cm] {angle = A--B--C};
\draw (B) -- (1.2,0);
\draw (B) -- (0.84585,0.84585);
\end{tikzpicture}%
}%
}

\usepackage{tikz}
\usetikzlibrary{angles}

\begin{document}

$\measuredangle$ \doubledmeasuredangle

{\large

$\measuredangle$ \doubledmeasuredangle
}
\end{document}


Improved version

\documentclass{article}
\usepackage{amssymb}
\usepackage{mathtools}

\usepackage{tikz}
\usetikzlibrary{angles}
\def\measuredangleangle{45}

\newsavebox{\tempboxa}
\newcommand{\doubledmeasuredangle}[1][.]{%
\savebox{\tempboxa}{$\measuredangle$}%
\resizebox{\wd\tempboxa}{\ht\tempboxa}{%
\begin{tikzpicture}[line width=1.75,line join=round,line cap=round,#1]
\pgfmathcos{\measuredangleangle};
\edef\temppgfmathone{\pgfmathresult}
\pgfmathsin{\measuredangleangle};
\edef\temppgfmathtwo{\pgfmathresult}
\typeout{\temppgfmathtwo\space \temppgfmathone}
\draw (1,0.0) coordinate (A) -- (0,0) coordinate (B)
-- (\temppgfmathone,\temppgfmathtwo) coordinate (C)
pic [draw,line width=1.75,angle radius=0.5cm] {angle = A--B--C}
pic [draw,line width=1.75,angle radius=0.25cm] {angle = A--B--C};
\pgfmathparse{tan(\measuredangleangle)};
\edef\temppgfmathtwo{\pgfmathresult}
\coordinate (FinalB) at (1.0,\pgfmathresult);
\draw (B) -- (FinalB);
\end{tikzpicture}%
}%
}

\begin{document}
\textcolor{blue}{$\measuredangle$ \doubledmeasuredangle}

{\large
$\measuredangle$ \doubledmeasuredangle
}
\end{document}


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I think it looks better with the two arcs closer, as in egreg's answer – User Feb 20 at 11:01
@User: That's a personal opinion. I leave that to the O.P. – Christian Hupfer Feb 20 at 11:07
Besides moving the two arcs closer, I'd recommend line width=1.75, line cap=round, join=round to get it closer to the other symbol. – Peter Grill Feb 20 at 11:49
@PeterGrill: I am working already on a better version, thanks -- and I have found the round values too. – Christian Hupfer Feb 20 at 11:55