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I am using the circuits.ee.IEC library. However, I cannot find any fuse symbol like this:

fuse symbol

How can I define such a symbol using circuit declare symbol? It should be just combining the resistor symbol and a line in some way, but I don't understand the syntax well enough to do this.

share|improve this question
You can greatly simplify and use the answer in this question. – percusse Nov 26 '11 at 22:04
@percusse Could you point out, how to do this, for resistor there is no IEC/before background path... – student Nov 26 '11 at 22:18
@percusse: A tip: If you copy-and-paste the entire link of a question you want to link to, e.g. http://tex.stackexchange.com/questions/7438/ac-source-symbol-in-tikz-circuits-e‌​e-iec-library, it'll automatically be shortened and people will see the question title as a hover-tooltip, which is more helpful than a "this question": tex.stackexchange.com/questions/7438/… – doncherry Nov 27 '11 at 9:02
@doncherry I thought it is less disruptive but apparently the hovering is a nice functionality. Thanks! – percusse Nov 27 '11 at 12:33
up vote 9 down vote accepted

A different approach would be to append code after the resistor node, similar to the light emitting and direction info styles:




    fuse graphic/.style={
        append after command={% At the end of the \draw command, do the following
            \bgroup % Start a new group
                [current point is local=true, % Do not influence the current point on the path
                every fuse/.try, % If `every fuse` has been defined, use it
                #1] % Apply options supplied by user
                (\tikzlastnode.west) edge [line to] (\tikzlastnode.east) % An edge, i.e. an independent path, from the west to the east of the resistor node
            \egroup% End the group
    fuse/.style={resistor={fuse graphic=#1}} % The fuse is just a resistor node with the `fuse graphics` key

\begin{tikzpicture}[circuit ee IEC]
    \draw (0,0) to [fuse] (2,0)  to [fuse] (0,-2) to [fuse] (0,0);

share|improve this answer
Thanks very much! Perhaps it would be nice to add some comments to your code to make it easier to adapt it to other examples for people who doesn't have a very deep knowledge of pgf/tikz. – student Nov 27 '11 at 9:24
@user4011: Done – Jake Nov 27 '11 at 9:40
Thanks again!!! – student Nov 27 '11 at 9:55

You can use annotations as described in the TikZ/PGF manual in Section 29.2.5 Declaring and Using Annotations to add the horizontal line over the symbol:

Annotations are quite similar to info labels. The main difference is that they generally cause something to be drawn by default rather than some text to be added (although an annotation might also add some text).

Here is an example of resistor and the fuse that you want:

enter image description here


  • This is my first attempt with annotations, and I am not sure about the coordinates used in the edge operation below. As per the comment by @GonzaloMedina, I have tweaked the coordinates by (0,-0.5\pgflinewidth) to adjust for the width of the rule. However, this still seems a bit of hack and feel that there should be a better way.
  • The transform shape option is what makes the fuse points along the path.



\tikzset{circuit declare annotation=
    {edge[to path={[-]
        --  ($( 0.5,-0.5\tikzcircuitssizeunit)+(0,-0.5\pgflinewidth)$)}] ()}

\tikzset{circuit declare symbol=fuse, 
    set fuse graphic={
        circuit symbol size=width 4 height 1, 
    transform shape}

  \begin{tikzpicture}[circuit ee IEC]
    \draw (0,1.0) to [resistor] (3,1.0) node [right] {resistor};
    \draw (0,0.5) to [fuse]     (3,0.5) node [right] {fuse};
    \draw (0,0.5) to [fuse] (0,-2) to [fuse] (3,0.5);
share|improve this answer
You forgot to take into account the width of the rule, so using something like ($(-0.5,-0.5\tikzcircuitssizeunit)+(0,-0.4pt)$) -- ($(0.5,-0.5\tikzcircuitssizeunit)+(0,-0.4pt)$)}] ()} would be better (of course, loading the calc library). – Gonzalo Medina Nov 27 '11 at 1:51
Or using -\pgflinewidth instead of -0.4pt above. – Gonzalo Medina Nov 27 '11 at 1:57
@GonzaloMedina: Thanks. Had to use exactly half the value you suggested to get this to work. – Peter Grill Nov 27 '11 at 2:05
@PeterGrill Thanks, however It doesn't work for me if I draw a vertical path, see my edit above. – student Nov 27 '11 at 8:08
@user4011: See updated solution. Adding the transform shape allows the node to point along the path. – Peter Grill Nov 27 '11 at 17:42

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