# ‘A’ with a lower-case omega on top

How can I write this in TeX (or LaTeX)?

Also, strictly speaking, this is not part of my question, but has anyone seen notation like this? If so, please answer this question.

-
Does \stackrel{\omega}{A} help? :) –  Paulo Cereda Nov 30 '11 at 15:38
Close, but the omega is a bit off to the left. –  Paul Reiners Nov 30 '11 at 15:46
possible duplicate of Customized accent symbol –  Leo Liu Nov 30 '11 at 16:00

\documentclass{article}
\usepackage{accents}

\begin{document}
$\accentset{\omega}{A}$
\end{document}

-
\usepackage{amsmath}

\overset{\omega}{A}


Never seen such a beast.

-

You may use \stackrel with some movement magic:

\documentclass{article}

\begin{document}
$\stackrel{\enskip\omega}{A}$
\end{document}


with result:

Or if you need it sans serif italic like you've shown:

\documentclass{article}
\begin{document}
$\stackrel{\,\,\omega}{\textsf{\textit{A}}}$
\end{document}


A very nice solution would be to use package accents, that prevents you from using any movement magic, als long as you are using math fonts only:

\documentclass{article}
\usepackage{accents}

\begin{document}
Nice:
$\accentset{\omega}{A}$
Not so nice:
$\accentset{\omega}{\textsf{\textit{A}}}$
\end{document}

-

You can use \overset like this: $\overset{\omega}{A}$ but the result will not be great (the A is slanted and therefore the centering looks off. I like \operatorname* better, since it doesn't make the A slanted. You can use it like:

$\operatorname*{A}^\omega$


The results look like this (\overset above, \operatorname below):

I have never seen the notation before by the way.

-
With \operatorname you get wrong spacing. –  egreg Nov 30 '11 at 15:42
What, exactly, is rather wrong? –  Paul Reiners Nov 30 '11 at 15:43
@PaulReiners: The spacing to the left and right of the A will be off. If you feel the omega is off to the left, it's not. Just looks that way because the A is slanted. I like it better with the A upright. You could use \overset{\omega}{\textrm{A}} to make it look like the \operatorname approach and still get correct spacing. By the way, if you want to respond to someone (in this case egreg) use @egreg to have him notified. –  Roelof Spijker Nov 30 '11 at 15:53
@PaulReiners An operator carries with it spacing rules that are different from those regarding an ordinary symbol. Compare $A\operatorname*{A}$ and $AA$. –  egreg Dec 1 '11 at 8:34
Why not \overset{\omega}{\mathrm{A}}, without abusing \operatorname? –  egreg Dec 1 '11 at 8:35