You can try,
\[
\begin{array}{@{}cr}
& 1 \\
+ & 10 \\
\cline{2-2}
& 11
\end{array}
\]
You may want also to adjust the space between the columns by using
\setlength\arraycolsep{0.1em}

Edit: added numbering
There are many ways to number the equations, but for this type of problem, I would either use the multienum package or incorporate the numbering in the array manually, or create a counter to auto increment. Here is a rather longer example. Of course it will look better if the + sign was on the right like we do in my part of the world.

\documentclass[fleqn]{article}
\usepackage{amsmath,multienum,booktabs}
\renewcommand{\regularlisti}{\setcounter{multienumi}{0}%
\renewcommand{\labelenumi}%
{\addtocounter{multienumi}{1}\alph{multienumi})}}
\begin{document}
\[
\begin{array}{lrr}
\text{(i)}& & 1 \\
&+ & 10 \\
\cmidrule(lr){3-3}
& & 11 \\
\end{array}
\]
\[
\begin{array}{lrr}
\text{(ii)}& & 1 \\
&+ & 10 \\
\cmidrule(lr){3-3}
& & 11 \\
\end{array}
\]
\[
\begin{array}{crr@{}c@{}r@{}c@{}l}
\text{(iii)} &237 &100a &{}+{}&10b &{}+{}&c\\
\addlinespace
\text{(iv)} &732 &100c &{}+{}&10b &{}+{}&a\\
\cmidrule(lr){2-2}\cmidrule(lr){3-7}
\text{(v)} &495 &\multicolumn{1}{l@{}}{100(a-c-1)} &+&90 &+&(10+c-a)\\
\addlinespace
\text{(vi)} &594 &\multicolumn{1}{l@{}}{100(10+c-a)} &+&90 &+&(a-c-1)\\
\cmidrule(lr){2-2}\cmidrule(lr){3-7}
\text{(vii)} &1089 &\multicolumn{1}{c}{900} &+&180 &+&9\\
\cmidrule(lr){2-2}\cmidrule(lr){3-7}
\specialrule{0pt}{-1pt}{-1pt}
\cmidrule(lr){2-2}\cmidrule(lr){3-7}
\end{array}
\]
\end{document}
\end{document}