# how to draw a hexagonal grid with numbers in the cells

The problem of drawing hexagonal grids has been discussed here: Drawing Hexagons

I want the shape of the grid to be hexagonal and furthermore, I want to be able to add numbers in the hexagonal cells. Any idea?

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I am basically trying to create a honey sudoku puzzle. –  Carl Jun 27 '12 at 15:15
Please add which drawing package you are using, how far you got (your current code) and where you are stuck. –  Caramdir Jun 27 '12 at 15:19
I have not implemented any code. I am a very beginner in latex. I would like the shape of the board to be hexagonal, like in this picture: img73.imageshack.us/img73/14/minesperfectportablenj3.png –  Carl Jun 27 '12 at 16:19

I'm not sure I understood correctly the question. I forgot to add name at each cell.

Update

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{shapes}

\begin{document}
\begin{tikzpicture} [hexa/.style= {shape=regular polygon,regular polygon sides=6,minimum size=1cm, draw,inner sep=0,anchor=south,fill=lightgray!85!blue,rotate=30}]
\foreach \j in {0,...,5}{%
\pgfmathsetmacro\end{5+\j}
\foreach \i in {0,...,\end}{%
\node[hexa] (h\i;\j) at ({(\i-\j/2)*sin(60)},{\j*0.75}) {};}  }
\foreach \j in {0,...,4}{%
\pgfmathsetmacro\end{9-\j}
\foreach \i in {0,...,\end}{%
\pgfmathtruncatemacro\k{\j+6}
\node[hexa] (h\i;\k) at ({(\i+\j/2-2)*sin(60)},{4.5+\j*0.75}) {};}  }

\foreach \k in {0,...,10}  {\node [circle,red,minimum size=1cm] at (h3;\k) {3;\k};}
\foreach \k in {0,...,10}  {\node [circle,blue,minimum size=1cm] at (h1;\k) {1;\k};}
\end{tikzpicture}
\end{document}


\documentclass{standalone}
\usepackage{tikz}
\usetikzlibrary{shapes}

\begin{document}
\begin{tikzpicture} [hexa/.style= {shape=regular polygon,
regular polygon sides=6,
minimum size=1cm, draw,
inner sep=0,anchor=south,
fill=lightgray!85!blue}]

\foreach \j in {0,...,9}{%
\ifodd\j
\foreach \i in {0,...,9}{\node[hexa] (h\j;\i) at ({\j/2+\j/4},{(\i+1/2)*sin(60)}) {\j;\i};}
\else
\foreach \i in {0,...,9}{\node[hexa] (h\j;\i) at ({\j/2+\j/4},{\i*sin(60)}) {\j;\i};}
\fi}
\node [circle,draw,red,minimum size=1cm] at (h3;4){};
\end{tikzpicture}
\end{document}


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Maybe better to state that this requires the CVS version. –  percusse Jun 27 '12 at 15:52
@percusse Why ? I used \ifodd and not \isodd ! –  Alain Matthes Jun 27 '12 at 15:56
Ah sorry. My bad. You are right. –  percusse Jun 27 '12 at 16:09
Great! thanx alot! –  Carl Jun 27 '12 at 17:20

Not very pretty, but with the code in this answer, numbers can be added if you calculate the coordinates:

\documentclass{article}
\usepackage{tikz}
\begin{document}

\begin{tikzpicture}[x=1cm,y=-1cm]
\foreach \i in {0,...,3}
\foreach \j in {0,...,3} {
\foreach \a in {0,120,-120} \draw (3*\i,2*sin{60}*\j) -- +(\a:1);
\foreach \a in {0,120,-120} \draw (3*\i+3*cos{60},2*sin{60}*\j+sin{60}) -- +(\a:1);}

\foreach \i in {0,...,3}
\foreach \j in {0,...,3} {
\node at (3*\i+2,2*sin{60}*\j) {\small $\i^+,\j$};
\node at (3*\i+0.5,2*sin{60}*\j+sin{60}) {\small $\i,\j$};}
\end{tikzpicture}

\end{document}


So, if you just want to number some of the hexagons, that may be good enough.

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Thanks that is very helpful. However, I am getting the following error when I run the code:"Package PGF Math Error: Unknown function sin60'" –  Carl Jun 27 '12 at 16:35
@Carl Probably a version mismatch, I guess. It worked for me with tikz` version 1.76 (2010/10/13) –  Jellby Jun 27 '12 at 16:47