Take the 2-minute tour ×
TeX - LaTeX Stack Exchange is a question and answer site for users of TeX, LaTeX, ConTeXt, and related typesetting systems. It's 100% free, no registration required.

enter image description here

The numbers are in Persian (side SB=6 and angle SBA=60 degrees).

share|improve this question
    

2 Answers 2

A solution with tkz-euclide but I made a mistake (HBS=60 and not SBA). Your example shows HBS ??. It's easy to make the same thing with TikZ but perhaps you can place some points like A,B,C,S and after we can help you to finish your drawing.

\documentclass[11pt]{article}
\usepackage{tkz-euclide}
\usetkzobj{all}

\begin{document}
\begin{tikzpicture}
\tkzDefPoint(0,0){B}
\tkzDefPoint(4,0){C} 
\tkzDefPoint(60:6){S}
\tkzDefPoint(30:3){A}
\tkzDefPointWith[colinear= at S](B,A)   \tkzGetPoint{I}   
\tkzDefPointBy[projection=onto B--C](S) \tkzGetPoint{H}
\tkzDefPointWith[colinear= at S](B,C)   \tkzGetPoint{D} 
\tkzDrawPolygon(S,D,I)
\tkzDrawSegments(B,C S,H B,S C,D)
\tkzDrawSegments[dashed](A,C A,B A,I)   
\tkzLabelPoints[below right](C,D,H) 
\tkzLabelPoints[above left](A,B,S,I)
\tkzMarkRightAngle[fill=lightgray](B,H,S)
\tkzMarkAngle[mark=|,arc=||,size=.5 cm,mkcolor=gray](C,B,S)
\tkzLabelAngle[pos=1,circle,fill=white](C,B,S){$60^{\circ}$}
\tkzLabelSegment[left](B,S){6}              
\end{tikzpicture}
\end{document}

enter image description here

Update

The definition of the coordinates with TikZ are given by

  \begin{tikzpicture}
   \coordinate (B) at (0,0);
   \coordinate (C) at (4,0);
   \coordinate (S) at (60:6);
   \coordinate (D) at ($(60:6)+(C)-(B)$);
   \coordinate (A) at (30:3);
   \coordinate (I) at ($(60:6)+(A)-(B)$);  
   \coordinate (H) at ($(B)!(S)!(C)$);
   \draw (D) -- (S) -- node[left] {6}(B)--(C) --  cycle; 
   \draw (S) -- (H);
   \draw[dashed] (B) -- (A) --(C) (I) -- (A);
   \draw (S) -- (I) -- (D); 
  \end{tikzpicture}
share|improve this answer

Compile the following with either xelatex or latex-dvips-ps2pdf.

enter image description here

\documentclass[border=12pt]{standalone}
\usepackage{pst-eucl}

\begin{document}
\begin{pspicture}[showgrid=false](9.2,7.7)
    \psset{PointSymbol=none}
    \pstTriangle[PosAngleA=-140,PosAngleC=135](0,0){B}(5,0){C}(3,2){A}
    \pstGeonode[PointName=none](0,0){M}(4,6){N}
    \pstTranslation[PointName={none,S,D},CurveType=polygon,PosAngle={0,135,0}]{M}{N}{A,B,C}
    \pstLineAB[linestyle=dashed]{A}{A'}
    \pstLineAB{B}{B'}
    \pstLineAB{C}{C'}
    \pstGeonode[PosAngle=-90,PointNameSep=7pt](B'|B){H}
    \pstLineAB{B'}{H}
    \pspolygon[fillstyle=solid,fillcolor=gray,opacity=0.5](B)(H)(B')
    \pstRightAngle{B}{H}{B'}
\end{pspicture}
\end{document}
share|improve this answer
    
The remaining labels are intentionally left as your homework. –  Please don't touch Jul 2 '12 at 19:20

Your Answer

 
discard

By posting your answer, you agree to the privacy policy and terms of service.

Not the answer you're looking for? Browse other questions tagged or ask your own question.