# Specifying the transformation matrix TikZ uses manually?

I'm creating some 3D graphics using TikZ, and I need to apply a transformation matrix to some coordinates I'm specifying in 2D so they end up in 3D. I am going to draw graphics on all three visible sides of a cube, and I have defined macros that work in 2D that I want to be able to use on those sides. Is there any way to do this? I saw that there are some primitive transformations in PGF, but they all work in 2D.

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\documentclass[parskip]{scrartcl}
\usepackage[margin=15mm]{geometry}
\usepackage{tikz}
\usetikzlibrary{3d}

\begin{document}

\tikzset{xzplane/.style={canvas is xz plane at y=#1,very thin}}
\tikzset{yzplane/.style={canvas is yz plane at x=#1,very thin}}
\tikzset{xyplane/.style={canvas is xy plane at z=#1,very thin}}

\begin{tikzpicture}[x={(0.985cm,-0.174cm)},y={(-0.906cm,-0.423cm)},z={(0cm,1cm)}]
\draw[xzplane=5] (0,0) -- (5,0) -- (5,5) -- (0,5) -- cycle;
\draw[yzplane=5] (0,0) -- (5,0) -- (5,5) -- (0,5) -- cycle;
\draw[xyplane=5] (0,0) -- (5,0) -- (5,5) -- (0,5) -- cycle;
\foreach \x in {xzplane,yzplane,xyplane}
{   \draw[\x=5] (1,1) -- (4,1) -- (2.5,4) -- cycle;
\filldraw[\x=5,red,fill opacity=0.2,draw=black] (1.5,1.5) circle (0.5);
\filldraw[\x=5,green,fill opacity=0.2,draw=black] (3.5,1.5) circle (0.5);
\filldraw[\x=5,blue,fill opacity=0.2,draw=black] (1.5,3.5) circle (0.5);
\filldraw[\x=5,yellow,fill opacity=0.2,draw=black] (3.5,3.5) circle (0.5);
}
\end{tikzpicture}

\end{document}


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That definitely seems like a way to go if you want to make a cube like in my case, thank you very much. What if you want to define an arbitrary plane, like x+2y+z=3 or something like that, is that possible? –  StrawberryFieldsForever Jul 13 '12 at 11:47
Hmm, I don't think this will be possible with the mechanism I used. Also, with non-orthogonal another problem arises: you must specify the origin and the axes on the plane. I think you should ask another question about this. –  Tom Bombadil Jul 13 '12 at 16:02