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I have a question similar to TikZ Fading Speed and defining a fading-style directly in the fill command but I can't figure out how to get a nice solution. I would like to, given a list of increasing integers from 0 to 100, generate the following piece of code:

\tikzfading[name=fade right0,left color=transparent!0, right color=transparent!70]
\tikzfading[name=fade right1,left color=transparent!70, right color=transparent!100]
\begin{tikzpicture}[start chain=1 going right,node distance=-0.15mm]
    \node [on chain=1] at (-1.5,-.4) {\ldots};
    \node [draw,dashed,on chain=1] {};
    \node [draw,dashed,on chain=1] {};
    \node [draw, dashed, path fading=fade right0, on chain=1] {};
    \node [draw, dashed, path fading=fade right1, on chain=1] {};

Here, obviously my list is {0, 70, 100}. I would like to use a foreach loop inide my tikzpicture, but I can't place the \tikzfading inside the tikzpicture, and I didn't suceed in using the answer from the above-mentioned post, could someone help me out ?


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1 Answer

up vote 4 down vote accepted

You can do it by the following

\foreach \x[remember=\x as \lastx,count=\xi from 0] in {20,40,70,100}{
\tikzfading[name=fade right\xi,left color=transparent!\lastx, right color=transparent!\x]

\begin{tikzpicture}[start chain=1 going right,node distance=-0.15mm,]
    \node [fill, dashed, path fading=fade right0, on chain=1] {};
    \node [fill, dashed, path fading=fade right1, on chain=1] {};
    \node [fill, dashed, path fading=fade right2, on chain=1] {};
    \node [fill, dashed, path fading=fade right3, on chain=1] {};

Well spotted by canaaerus that initially option causes some trouble. There was another question where I had the same problem but I couldn't find it. It's best to define \lastx out of the loop.

enter image description here

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It seems like \lastx is always 0!?! –  canaaerus Aug 3 '12 at 10:31
@canaaerus You are right, it happened to me before with initially option. I'll fix it in a sec. –  percusse Aug 3 '12 at 10:38
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