How to use angle option when using ([angle=number]{node1} node2) notation?

Question

According to PSTricks manual, as shown in the screenshot below, there is an optional angle option.

Unfortunately, the example above does not show how to use angle option.

I have tried using angle but I always fail. The option does not affect anything.

\documentclass[border=12pt]{standalone}  
\usepackage{pst-eucl,multido}

\begin{document}
\multido{\i=0+30}{3}{%
\begin{pspicture}[showgrid](6,6)
    \pstGeonode(0,5){B}(3,3){A}
    \pstLineAB[nodesepB=-3]{B}{A}
    \pstCircleOA[Radius=\pstDistVal{1},linestyle=dashed]{A}{}
    \uput{1.5}[90](A){angle=$\i^\circ$}
    \psline[linecolor=blue]([offset=1,angle=\i]{B}A)% does not affect anything!
\end{pspicture}\hspace{5mm}}

\end{document}

How to use angle option when using ([angle=number]{node1} node2) notation?

Answer 1

\documentclass{article}  
\usepackage{pst-node}\SpecialCoor

\begin{document}
\begin{pspicture}[showgrid](4,4)
  \pnode(3,3){A}\psdot[dotscale=2](A)\uput[135](A){A}
  \pnode(4,0){B}\psline[linestyle=dotted](A)(B)
  \pscircle[linestyle=dotted](A){1}
  \psline([nodesep=1]A)                \uput[0](3.5,2){I}
  \psline[linecolor=red]([nodesep=-1]A)\uput[-45](2,4){II}
  \psline[linecolor=blue]([offset=1]A) \uput[-225](4,4){III}
  \psline[linecolor=green]([offset=1]A)\uput[0](2,2){IV}
\end{pspicture}
\qquad
\begin{pspicture}[showgrid](4,4)
  \pnode(3,3){A}\psdot[dotscale=2](A)\uput[135](A){A}
  \pnode(4,0){B}\psline[linestyle=dotted](A)(B)
  \pscircle[linestyle=dotted](A){1}
  \psline([nodesep=1,angle=-45]A)                \uput[0](3.5,2){I}
  \psline[linecolor=red]([nodesep=-1,angle=-45]A)\uput[-45](2,4){II}
  \psline[linecolor=blue]([offset=1,angle=-45]A) \uput[-225](4,4){III}
  \psline[linecolor=green]([offset=1,angle=135]A)\uput[0](2,2){IV}
\end{pspicture}
\qquad
\begin{pspicture}[showgrid](4,4)
  \pnode(3,3){A}\psdot[dotscale=2](A)\uput[135](A){A}
  \pnode(4,0){B}\psline[linestyle=dotted](A)(B)
  \pscircle[linestyle=dotted](A){1}
  \psline([nodesep=1,angle=-45]{B}A)                \uput[0](3.5,2){I}
  \psline[linecolor=red]([nodesep=-1,angle=-45]{B}A)\uput[-45](2,4){II}
  \psline[linecolor=blue]([offset=1,angle=-45]{B}A) \uput[-225](4,4){III}
  \psline[linecolor=green]([offset=1,angle=135]{B}A)\uput[0](2,2){IV}
\end{pspicture}

\end{document}

Answer 2

I can say, with some degree of certainty, that it is a typo since ([angle=number]{node1} node2) has the constraint that the result should be on the virtual line connecting A to B. So an additional angle option would be confusing. The angle is working just fine when you have ([angle=number]node) syntax :

\documentclass[border=12pt,pstricks]{standalone}  
\usepackage{pst-eucl}
\begin{document}
\begin{pspicture}[showgrid](6,6)
    \pstGeonode(0,5){B}(3,3){A}
    \pstCircleOA[Radius=\pstDistVal{1},linestyle=dashed]{A}{}
    \psline[linecolor=blue]([angle=-90,nodesep=1]B)
    ([angle=45,nodesep=1.414]A)
\end{pspicture}
\end{document}

In the relative point syntax the virtual line from (B) to (A) is the nodesep direction and normal to that line at (A) is the offset direction.

\documentclass[border=12pt,pstricks]{standalone}  
\usepackage{pst-eucl}
\begin{document}
\begin{pspicture}[showgrid](4,4)
    \pstGeonode(0,4){B}(3,3){A}
    \pstCircleOA[Radius=\pstDistVal{1},linestyle=dashed]{A}{}
    \psline[linecolor=blue]([nodesep=2]{B}A)(A)([offset=2]{B}A)
    \psline[linecolor=green]([offset=0.1]{B}A)
    \psline[linecolor=green]([offset=0.3]{B}A)
    \psline[linecolor=green]([offset=0.5]{B}A)
    \psline[linecolor=green]([offset=0.7]{B}A)
    \psline[linecolor=green]([offset=0.9]{B}A)
    \psline[linecolor=green]([offset=1.1]{B}A)
\end{pspicture}
\end{document}

Answer 3

Using angle option might be a feature that has not been implemented.