# About big parenthesis larger than Bigg

Do any one know how to type a very big parenthesis in LaTeX. Since the formula is very big, I used multline environment, in one line, there are many pair of parenthesis by using \left and \right which make them already very big. Between lines, I need some parenthesis bigger than the one given by \Bigg. My intention is to show the following big formula in multline environment:

$$\frac{ e^{-\frac{t \lambda +4}{4 \lambda \nu }} \left( e^{\frac{t}{4 \nu }} \left( 4 \sqrt{\pi } \sqrt{\nu }+1 \right) \nu \Phi \left( \frac{t-\frac{2}{\lambda }}{\sqrt{2} \sqrt{t \nu }} \right) \lambda^3 -e^{\frac{t \lambda +8}{4 \lambda \nu }} \left( 4 \sqrt{\pi } \sqrt{\nu }-1 \right) \nu \left( \Phi \left( \frac{t+\frac{2}{\lambda }}{\sqrt{2} \sqrt{t \nu }} \right) -1 \right) \lambda^3 +e^{\frac{1}{\lambda \nu }} \left( 4 \sqrt{\pi } \lambda^3 \nu^{3/2} \left( 2 \Phi \left( \frac{1}{\sqrt{2} \lambda \sqrt{t \nu }} \right) -1 \right) -e^{\frac{t}{4 \nu }} \left( \left( \lambda \left( 4 \sqrt{\pi } \sqrt{\nu }-1 \right) \nu +2 \right) \lambda^2+2 (\lambda \nu -2) \Phi \left( \frac{\sqrt{\frac{t}{\nu }}}{\sqrt{2}} \right) \lambda^2-2 \right) \right) \right) }{4 \lambda }$$

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(tried to clean up the code a little for you) –  Loop Space Dec 9 '10 at 10:05
Thank you Andrew. It is very nice of you. :-) –  Anand Dec 9 '10 at 10:28
Note that $$...$$ should not be used for displayed math, cf. l2tabu: ctan.org/tex-archive/help/Catalogue/entries/l2tabu.html –  Torbjørn T. Dec 9 '10 at 10:44
@Torbjorn, shall we use "" instead? Thanks. :-) –  Anand Dec 9 '10 at 13:18
@anand: Yes, that or the equation* environment. Sorry, should have mentioned this in my previous comment. See also here and here. –  Torbjørn T. Dec 9 '10 at 16:22

The ams parenthesis of specific size are typeset by using \left and \right and putting in an invisible "thing" of a certain height to ensure that they are big enough. Mimicking that, you could do: \left(\rule{0cm}{2cm}\right. to get a left parenthesis of 2cm height. Note that the AMS command also adds a little horizontal space which you might need to put in as well. If you do this often, you could easily define new sizes:

\makeatletter
\newcommand{\vast}{\bBigg@{4}}
\newcommand{\Vast}{\bBigg@{5}}
\makeatother


$\Vast( \frac{\prod_0^\infty k}{\sum_0^\infty n} \Vast)$


produces:

I recommend also taking a look at Vertically asymmetric size variation for parentheses about vertically centring parentheses.

(Note I've assumed that you're using amsmath since you tag it with amsmath and the commands \big and so forth are ones that amsmath produces. If you're using a different package to get these commands, then this solution won't work.)

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Thank you Andrew. It is very useful. It solves my problem. :-) –  Anand Dec 9 '10 at 10:30
very useful thanks a lot you are an angel !! –  user11861 Feb 18 '12 at 4:30
Great, but your code should also define \vastl, \vastm, and \vastr commands that work along the lines of \bigl, \bigm, and \bigr, right? Also \Vastl, \Vastm, and \Vastr? –  MSC Dec 7 '13 at 0:49