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I apologize if this question has been asked. I think it should be fairly simple, but I've looked around a bit and I can't find anything that does what I'm looking for.

I know you can calculate, e.g., the point 10% of the way between two nodes:

\node (A) at (0,0) {};
\node (B) at (1,0) {};
\coordinate (C) at ($(A)!0.1!(B)$);

But what if I were drawing a bent line between nodes A and B:

\draw (A) to [bend left=30] (B);

How to I calculate the coordinate that is 10% of the way along this bent path?

Thanks in advance.

share|improve this question
up vote 7 down vote accepted

You can use \path (A) to [bend left=30] coordinate [pos=0.1] (C) (B) to place a coordinate at a specified distance along the path:


\node (A) {A};
\node (B) at (2,0) {B};
\draw (A) to [bend left=30] (B);
\path (A) to [bend left=30] coordinate [pos=0.1] (C) coordinate [pos=0.7] (D) (B) ;
\fill [red] (C) circle [radius=2pt] (D) circle [radius=2pt];

share|improve this answer
Thanks, that worked perfectly! – user18452 Sep 7 '12 at 14:10

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