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I'm looking a way of making something like this:

\underbrace{
    \left[\nabla\times
    \left[\nabla\times
    \left[\ldots\nabla\times
}_{
    \infty\text{-times taking curl operator}
}
    \mathbf{V}\right]\right]\ldots\right] = ?
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1  
Related: Left/Right across multiline equation and \left and \right in equation across multiple lines (applies to terms in different scopes as well) –  Qrrbrbirlbel Nov 10 '12 at 19:48
2  
Three \lefts and four \rights by the way … :) –  Qrrbrbirlbel Nov 10 '12 at 19:51
1  
I don't see a reason for \left and \right here since they don't contain anything large. Wouldn't simple \underbrace{[\nabla\times[\nabla\times[\cdots\nabla\times}_{\infty\text{-times taking curl operator}}\mathbf{V}]]\cdots] work? –  tohecz Nov 11 '12 at 8:41
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marked as duplicate by percusse, egreg, tohecz, Werner, Heiko Oberdiek Aug 21 '13 at 5:24

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1 Answer

up vote 1 down vote accepted

It's easy to achieve this inserting an appropriate \right and \left null delimiters:

\left.
\right.

The correspondent code would be:

\underbrace{
    \left[\nabla\times
    \left[\nabla\times
    \left[\ldots\nabla\times
    \right.\right.\right.
}_{
    \infty\text{-times taking curl operator}
}
    \mathbf{V}\left.\left.\left.\right]\right]\right]\ldots\right] = ?
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3  
Either setting \nulldelimiterspace=0pt inside the formula or adding \kern-3\nulldelimiterspace (or \kern-4\nulldelimiterspace) help to get rid of the additional spacing by \left. or \right.. –  Heiko Oberdiek Nov 10 '12 at 19:57
    
As far as I see, your solution would not wrong if there were \frac{V}{W} instead of \mathbf{V}. I think that \vphantom should be used here at the proper places. –  tohecz Nov 11 '12 at 8:43
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