How to create a Markov chain with an empty node

Question

I would create using tikz package this Markov chain but I encountered many problems. Who can post the right code to create the follow Markov chain?

Answer 1

The positioning library

Code

\documentclass[tikz]{standalone}
\usetikzlibrary{automata,positioning}
\begin{document}
\begin{tikzpicture}
\node[state]                               (0) {0};
\node[state,right=of 0]                    (1) {1};
\node[state,right=of 1]                    (2) {2};
\coordinate[draw=none,right=of 2]          (2-g);
\node[state,right=of {2-g},text depth=0pt] (g) {g};

\draw[
    >=latex,
%   every node/.style={above,midway},% either
    auto=right,                      % or
    loop above/.style={out=75,in=105,loop},
    every loop,
    ]
     (g)   edge[loop above] node {$p_{gg}$}   (g)
           edge             node {$p_{gg-1}$} (2-g)
     (2-g) to               node {$p_{32}$}   (2)
           edge[loop above] node {$p_{22}$}   (2)
     (2)   edge             node {$p_{21}$}   (1)
     (1)   edge[loop above] node {$p_{11}$}   (1)
           edge             node {$p_{10}$}   (0)
     (0)   edge[loop above] node {$p_{00}$}   (0);
\end{tikzpicture}
\end{document}

Output

---

Replacing the \coordinate line with

\node[draw=none,right=of 2]           (2-g) {text};

you get:

The chains library

Code

\documentclass[tikz]{standalone}
\usetikzlibrary{automata,chains}
\begin{document}
\begin{tikzpicture}[start chain=going right]
\node[state, on chain]                 (0) {0};
\node[state, on chain]                 (1) {1};
\node[state, on chain]                 (2) {2};
\node[on chain]                   (2-g) {text};
\node[state, on chain, text depth=0pt] (g) {g};

% The \draw path is like the one above.
\end{tikzpicture}
\end{document}

Output