I have the same question in here
In the answer, the author used beamertemplate to examine breaking the frames. But how can i change it to my paragraph?
For example, i need to insert the following problem and its solution
Problem : Solve
x^{3} - x -3=2\sqrt[3]{6x-3x^{2}}
Proof : Put a:=\sqrt[3]{6x-3x^2} to obtain a system
\begin{eqnarray}x^3-x-3 &=& 2a\\6x-3x^2 &=& a^3\end{eqnarray}
Add the equations up to get
x^3-3x^2+5x-3=a^3+2a
(x-1)^3+2(x-1)=a^3+2a
Put y:=x-1 to get
y^3+2y=a^3+2a
(y-a)(y^2+ay+a^2+2)=0
The second factor is obviously always positive, hence y=a\iff a=x-1
Now (1) yields x^3-x-3=2x-2\iff x^3-3x=1
Put x:=2t to get
8t^3-6t=1\iff 4t^3-3t={1\over 2}
By addition formulas, there must exist \phi such that t=\cos\phi, yielding
\cos 3\phi={1\over 2}\iff 3\phi=\pm{\pi\over 3}+2k\pi\iff \phi=\pm{\pi\over 9}+{2k\pi\over 3},k\in\mathbb{Z}
Now x=2\cos\phi=2\cos\left(\pm{\pi\over 9}+{2k\pi\over 3}\right), i.e.
x\in\left\{2\cos{\pi\over 9},2\cos{5\pi\over 9},2\cos{7\pi\over 9}\right\}
It may take more than one frame and i think the command allowbreakframes is useful. But i don't know how to exchange beamertemplate to my above paragraph. I also want to put the problem and the solution in blocks. Thanks for your listening my question!
minimal working exampleso we know what you tried so far. So far your question seems unclear what you're aiming at. – user24276 Feb 5 at 12:20add commentfunction. – Marco Daniel Feb 5 at 12:20