Tagged Questions

5
votes
2answers
58 views

Double subscript error with \newcommand?

Disclaimer: I know of Defining a newcommand with sub- or superscript and avoiding "double subscript" error but this only gives a work-around, but no explanation to my question. Here's a ...
7
votes
1answer
76 views

Can I detect whether my macro is being used inside a subscript or superscript?

I defined this macro: \newcommand{\foldeq}[1]{\sim_{#1}} Later on, I noticed that when it's used inside a subscript, it looks a little bit hard to tell whether it's $\sim f$ or $\sim_f$. ($\sim f$ ...
2
votes
1answer
151 views

relative hspace in newcommand

I'm trying to create a symbol of a gray triangle with a black border. I managed to do so using: \newcommand{\factor}{{\color{gray} \blacktriangledown}\hspace{-1.6ex}\triangledown} However, the two ...
5
votes
1answer
168 views

Redefine underscore on a per command basis.

Is it possible to redefine the underscore while within a particular command only? This is somewhat related to: Redefine underscore to produce roman subscript I would like: \mycmd --> S ...
4
votes
3answers
354 views

Redefine underscore to produce roman subscript without breaking file names

I've been using Hendrik Vogt's answer to my earlier question Redefine underscore to produce roman subscript, in which he explained how to make the underscore character active and assign a macro to it ...
7
votes
2answers
746 views

Redefine underscore to produce roman subscript

I would like to redefine the underscore _ to automatically set subscripts in math mode in roman type, as I currently find myself almost always using _\mathrm{}. I can't find a way of redefining what _ ...
10
votes
3answers
2k views

How to raise a subscript?

For some reason, I need to write a “minus” sign as a subscript on some symbols, but if I simply write $\Pi_{-}$ the result looks kind of odd. I've found that $\Pi{\scriptstyle -}$ looks reasonably ...
3
votes
2answers
199 views

Can super/sub-scripts bind more tightly than macro expansion?

By "bind more tightly" I refer to the order in which operations are carried out by default. Experimenting shows that if \ab is ab and \cd is cd then \ab^\cd is ab^cd. I would like it to be ...