New answers tagged

1

Here is a sample code in circuitikz which includes PZ as suggested by John Kormylo. \documentclass{article} \usepackage{tikz} \usepackage{circuitikz} \begin{document} \begin{figure}[h!] \begin{center} \begin{circuitikz} \draw (2,0) to [Tnpn,n=npn] (2,1.4) (npn.E) node[right=3mm, above=5mm]{$Q$}; % Label the transistor \...


0

It works fine without any error in the TexWork having latest Miktex update. I got no warning at all. May be you need to update your packages :-) \documentclass{article} \usepackage{tikz} \usepackage{circuitikz} \begin{document} \begin{figure}[htp!] \begin{center} \begin{circuitikz} \draw (0,4) to[C=$ASCII_TEXT$] (2,4); % The capacitor \draw (0,2) to[R=$...


0

Unfortunately, the circuitikz module does not acknowledge a plain european option. It rather takes a key=value list, akin to \ctikzset. Therefore, to obtain the european resistor, one has to pass resistor=european to the module. Also, you have to load the tikz module before circuitikz or the keys will no be parsed (I guess they are being silently ...


2

Since this version draws a symbol in the text area, I commented out the code for the text area (but left it there in case anyone wants to fix the american not port). \documentclass{standalone} \usepackage{circuitikz} \makeatletter \pgfdeclareshape{inverter} { \anchor{center}{\pgfpointorigin} % \anchor{text}{% this is used to center the text in ...


2

Probably you looking for something like this: You have a mismatch in your code. Correct is (observe position of to): \documentclass[border=5mm]{standalone} \usepackage{circuitikz} \begin{document} \begin{circuitikz} \draw (-0.5,0) to [short, o-] (0,0) to [R, l=$R_s$] (2,0) to [L, l=L] (4,0) to [short,...


2

They do not overlap, the grid is in the background, but the resistor shapes are not filled. Replace one of them by a filled shape, e.g. write fullgeneric=,... instead of R=... and you will see the grid disappear behind the shape. The circuitikz manual does not show an easy way to fill your shapes, otherwise you could have just filled the resistors with ...



Top 50 recent answers are included