# Tag Info

2

this does not exist as a "precomposed" symbol. however, amsmath provides a mechanism for creating combinations of this sort -- \overset: \documentclass{article} \usepackage{amsmath} \begin{document} $x \overset{0}{\equiv} y$ \end{document} when \overset is applied to a single symbol, the proper class of that symbol (e.g., \mathrel, \mathbin) is ...

3

It is not a long answer, and working in LaTeX, not plain TeX, but according to Werner's suggestion... \stackrel{?}{=}

3


2

You may want to have an abstract approach to this; we can exploit the fact that amsmath changes all operator names taking limits in a uniform way, by adding @ at the end of the name to mean the symbol. \documentclass{article} \usepackage{amsmath,etoolbox} \makeatletter \newtoggle{reducedop} \newcommand{\reduceoperatorsize}[1]{% \csletcs{#1saved}{#1}% ...

1

Based on comment discussion, I had suggested something similar to the answer at How are big operators defined?, in the form of \DeclareMathOperator*{\barr}{\textstyle\sum}. However, that approach still places displaystyle limits above and below the summation (ex. 1). Nonetheless, we know that the spacing provided by \barr in textstyle (ex. 2) is the proper ...

Top 50 recent answers are included