1,369 reputation
528
bio website bandes-storch.net
location Portland, OR
age 21
visits member for 2 years, 7 months
seen 2 days ago

I'm a college senior, computer geek/programmer, etc.
Twitter: @jtbandes.


Oct
30
accepted mathpazo + siunitx: π turns into ß
Oct
30
comment mathpazo + siunitx: π turns into ß
Thank you! That all makes sense, except for why mathpazo treats \pi weirdly inside mathrm in the first place in the first place...
Oct
30
comment mathpazo + siunitx: π turns into ß
Why does the output differ between math mode and inside the \SI command, with both siunitx and mathpazo?
Oct
30
revised mathpazo + siunitx: π turns into ß
edited title
Oct
30
asked mathpazo + siunitx: π turns into ß
Oct
24
accepted Vertically centered horizontal rule filling the rest of a line?
Oct
24
asked Vertically centered horizontal rule filling the rest of a line?
Oct
22
awarded  Cleanup
Oct
22
revised xfrac + siunitx gives me a font warning
rolled back to a previous revision
Oct
22
awarded  Commentator
Oct
22
revised Creating a font with blackboard characters for as many engines as possible?
removed signature
Oct
22
suggested suggested edit on Creating a font with blackboard characters for as many engines as possible?
Oct
22
comment xfrac + siunitx gives me a font warning
@Mico: I've put up more information and an example. It seems to be directly related to siunitx, rather than mathpazo or amsmath.
Oct
22
awarded  Editor
Oct
22
revised xfrac + siunitx gives me a font warning
added detailed information
Oct
22
asked xfrac + siunitx gives me a font warning
Oct
11
accepted How can I allow a command to be used without braces around its argument, when the argument has an argument?
Oct
10
comment How can I allow a command to be used without braces around its argument, when the argument has an argument?
So \v{f} counts as one token? Or is it just that when \v is expanded to yield #1 it eats the {f} argument?
Oct
10
comment How can I allow a command to be used without braces around its argument, when the argument has an argument?
I'm sure I just don't understand how expansion works yet, but when I see _\v{f}, I would think that expands to _{...contents of \v...}{f}. When/how does the {f} argument replace the #1 inside of \v?
Oct
10
comment How can I allow a command to be used without braces around its argument, when the argument has an argument?
Why does _\v{f} work as a subscript instead of being interpreted as _{\v}{f}?