Commutative diagrams with very round arrows? - TeX - LaTeX Stack Exchange most recent 30 from tex.stackexchange.com 2022-01-20T19:27:20Z https://tex.stackexchange.com/feeds/question/418880 https://creativecommons.org/licenses/by-sa/4.0/rdf https://tex.stackexchange.com/q/418880 1 Commutative diagrams with very round arrows? Tanda https://tex.stackexchange.com/users/125660 2018-03-07T11:34:40Z 2018-03-08T00:27:38Z <p>I have a diagram that has only objects in (1,1), (1,2) and (2,1). I would like an arrow that goes from (2,1) to (1.2) going around (1.1). I do succeed in curving the arrow, but not to make it round enough to avoid crossing other objects in the diagram. Here is what I have:</p> <pre><code>\documentclass{article} \usepackage[all]{xy} \usepackage{amscd,amssymb} \begin{document} \xymatrix{ p^{-1}(V)\ar[d]_p &amp;V\times Y\ar[l]_\varphi\ar[dl]^{\mathrm{pr}_1}\\ V\ar@/_/[u]_\sigma\ar@/^5pc/[ur]^\psi } \end{document} </code></pre> <p>Thanks!</p> https://tex.stackexchange.com/questions/418880/-/419022#419022 2 Answer by caverac for Commutative diagrams with very round arrows? caverac https://tex.stackexchange.com/users/152462 2018-03-08T00:27:38Z 2018-03-08T00:27:38Z <p>Here's a version using <code>tikz-cd</code></p> <pre><code>\documentclass[border = 5pt]{standalone} \usepackage{tikz-cd} \begin{document} \begin{tikzcd} p^{-1}(V) \arrow[d, "p"'] &amp; V\times Y \arrow[l, "\varphi"'] \arrow[dl, "\mathrm{pr}_1"] \\ V \arrow[u, bend right, "\sigma"'] \arrow[ur, rounded corners, "\psi", to path = { -- ([xshift = -4ex]\tikztostart.west) |- ([yshift = 3ex]\tikztotarget.north) [near end]\tikztonodes -- (\tikztotarget)}] \end{tikzcd} \end{document} </code></pre> <p><a href="https://i.stack.imgur.com/86Ulr.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/86Ulr.png" alt="enter image description here"></a></p>