The following does not work in LaTeX because logic symbols can only be used in maths mode:

\texttt{\forall x(\exists y((f(x)=y)\land(\neg(g(y)=y))))}

I want to do this to stress the nature of such formulas as strings (mathematical objects). The logic symbols should look more similar to the other fixed-width symbols than to normal maths mode symbols. I would then also be able to write the following:

If $\phi$ is a formula of first-order logic and $x$ is a variable, then
\texttt{\forall$x$($\phi$)} is again a formula of first-order logic.

What's the best way to do this? Obviously, using different commands instead of \forall, \land etc. is fine. Directly entering unicode maths characters would be even better:


If $\phi$ is a formula of first-order logic and $x$ is a variable, then
\texttt{∀$x$($\phi$)} is again a formula of first-order logic.

I tried XeTeX with \usepackage{utf8x} and it doesn't work. The negation symbol gives "Character172appearedalone", and the other characters are simply not printed.

[Added after first response]

The following is so far the best approximation:


\noindent\texttt{\Forall x\Exists y(x\Land y)}\\
\texttt{abcde\Forall x\Exists y(x\Land y)}

The usage example demonstrates that the logic symbols do not have precisely the right width. But it's sufficient for my needs, at least initially. I guess for the final solution I will look up how to make these symbols use width zero and print them over a monotype space character.

2 Answers 2


This is no problem with XeTeX if you load a font that contains these characters:



\setmainfont{DejaVu Serif}
\setsansfont{DejaVu Sans}
\setmonofont{DejaVu Sans Mono}



If $\phi$ is a formula of first-order logic and $x$ is a variable, then
\texttt{∀$x$($\phi$)} is again a formula of first-order logic.


Note: Never load the inputenc package when compiling with XeTeX.

  • Results using DejaVu Sans Mono: DejaVu Sans Mono

  • Results using FreeMono: FreeMono

  • I tried this on my system (MikTeX 2.8 on Windows XP, numerous special fonts installed): The \land and the \neg come out fine, but the quantifiers are missing in the PDF. I assume this is a font problem?
    – user3297
    Commented Feb 2, 2011 at 11:52
  • @Hans: Yes, you need to make sure that the monospace font selected via \setmonofont contains the characters in question. I chose DejaVu Sans Mono for my example because I know it contains them.
    – Philipp
    Commented Feb 2, 2011 at 12:00
  • @Philipp: I looked at my type 1 DejaVu Sans Mono font in a font viewer, and it turns out the quantifiers are present in it but wider than the other characters. Very odd. Perhaps that's why they don't appear in the PDF?
    – user3297
    Commented Feb 2, 2011 at 12:21
  • Actually, my font viewer displays the quantifiers in all my fonts, even the most exotic ones, and they tend to not fit into a font's general style. So I guess the font viewer takes them from fall-back fonts without telling me, and they are not actually present in my version of DejaVu Sans Mono. This page confirms that the quantifiers are not present in the font: xahlee.org/emacs/emacs_unicode_fonts.html Still looking for one that works, preferably with serifs.
    – user3297
    Commented Feb 2, 2011 at 12:31
  • DejaVu Sans Mono does contain ∀ and ∃, see the coverage table (page 24) or this page. I've added a screenshot of the result.
    – Philipp
    Commented Feb 2, 2011 at 13:29

can't you use $\mathtt{\forall x(\exists y((f(x)=y)\land(\neg(g(y)=y))))}$ ?

  • Thanks! I completely forgot about \mathtt. I am not completely happy with this because it's not fixed-width: In particular the parentheses are too narrow and the \land is even spaced as an operator. But I guess I can combine this with \texttt and create special commands for the operators to get the spacing approximately right.
    – user3297
    Commented Feb 2, 2011 at 11:09

You must log in to answer this question.