To have each of the three "columns" centered, you could use the array
environment. Note (i) the specification of the =
column dividers in the header of the array environment, to ensure math-appropriate spacing, and (ii) the reset of the \arraystretch
parameter to get a look that's appropriate for a group of displayed equations.
\documentclass{article}
\begin{document}
\renewcommand\arraystretch{1.33} % default value: 1.0
\[
\begin{array}{c @{{}={}} c @{{}={}} c}
v_2(16) & \frac{2}{5}[v_3(32)+v_3(8)] & 0, \\
v_2(4) & \frac{2}{5}[v_3(8) +v_3(2)] & 1.20,\\
v_2(1 ) & \frac{2}{5}[v_3(2) +v_3(0.50)] & 3.
\end{array}
\]
\end{document}

If you want to typeset the left-most column flush-right against the first =
sign and the right-most column flush-left against the second =
sign, you could set {r @{{}={}} c @{{}={}} l}
as the array header specification.
Rather than center-set the middle portions of the equations, I would actually recommend maintaining the alignat*
environment while adding a further alignment point, at the +
sign. I'd also use \tfrac
rather than frac
:
\documentclass{article}
\usepackage{amsmath}
\begin{document}
\begin{alignat*}{3}
v_2(16)&=\tfrac{2}{5}[v_3(32) &&+v_3(8)] &&= 0, \\
v_2(4) &=\tfrac{2}{5}[v_3(8) &&+v_3(2)] &&= 1.20,\\
v_2(1) &=\tfrac{2}{5}[v_3(2) &&+v_3(0.50)] &&= 3.
\end{alignat*}
\end{document}

{}
; I also removed the thanks, which is just our policy here- we like to say thanks by upvoting :) It helps keep the site more like a Q&A site- welcome! :) – cmhughes Mar 16 '13 at 19:17