Making a LaTeX version of a textual logotype

Question

I want to create a macro that typesets the text "julia" with two slanted dots above the "ia" at the end, so it looks like this:

   _       _ _(_)_     
  (_)     | (_) (_)    
   _ _   _| |_  __ _   
  | | | | | | |/ _` |  
  | | |_| | | | (_| |  
 _/ |\__'_|_|_|\__'_|  
|__/                   

Since \.a gives me a dotted a, I thought maybe I could use \.{i\.a} to produce the third dot, but it didn't work - jul\.{i\.a} just outputs "juli".

Actually, I'm looking to recreate the logo at julialang.org.

Is there a way to get all the dots there?

Answer 1

Here is my attempt.

I tried to emulate the original julia logo from julialang.org. Some features:

• The positioning of the dots is relative to the x-height of the current font, which means that they should stay in the right position if the font size changes.
• The word "julia" is set in the cmss (Computer Modern sans serif) font, which means the logo won't change if you change your default sans serif font to Helvetica or something.
• The \julia command is declared as a 'robust' command, which means that it can safely be used inside section headings and so on. See the picture below:

Here is my code:

\documentclass{article}

\usepackage{tikz}
\usetikzlibrary{positioning}
\usetikzlibrary{calc}

\definecolor{mylightred}{RGB}{211,79,73}
\definecolor{mydarkred}{RGB}{199,44,38}
\definecolor{mylightgreen}{RGB}{78,153,67}
\definecolor{mydarkgreen}{RGB}{43,129,33}
\definecolor{mylightpurple}{RGB}{150,107,178}
\definecolor{mydarkpurple}{RGB}{126,78,160}
\definecolor{mylightblue}{RGB}{49,101,205}
\definecolor{mydarkblue}{RGB}{20,92,205}

\tikzset{
  juliadot/.style args={#1,#2}{shape=circle,line width=0.03ex,minimum width=0.4ex,fill=#1,draw=#2}
}

\newcommand\julialetter[1]{{\strut\fontfamily{cmss}\bfseries\selectfont{#1}}}

\DeclareRobustCommand\julia{%
\begin{tikzpicture}[baseline=0mm, every node/.style={inner sep=0mm, outer sep=0mm}]
\node[anchor=base]        (j) at (0,0) {\julialetter{\j}};
\node[anchor=base, right=0ex of j] (u) {\julialetter{u}};
\node[anchor=base, right=0ex of u] (l) {\julialetter{l}};
\node[anchor=base, right=0ex of l] (i) {\julialetter{\i}};
\node[anchor=base, right=0ex of i] (a) {\julialetter{a}};
\path let \p1 = (j) in node[juliadot={mylightblue,mydarkblue}] (bluedot) at (\x1+0.02ex,1.4ex) {};
\path let \p1 = (i) in node[juliadot={mylightred,mydarkred}] (reddot) at (\x1,1.4ex) {};
\path let \p1 = (reddot) in node[juliadot={mylightpurple,mydarkpurple}] (purpledot) at (\x1+0.5ex,\y1) {};
\path let \p1 = (reddot) in node[juliadot={mylightgreen,mydarkgreen}] (greendot) at (\x1+0.25ex,\y1+0.42ex) {};
\end{tikzpicture}%
}

\begin{document}

\section{The \julia\ logo}

\parbox{8cm}{
\tiny Here is a {\julia} logo.
\small The {\julia} logo is made using TikZ.
\normalsize The dimensions in {\julia}'s logo are relative,
\large so {\julia} scales quite nicely,
\LARGE when {\julia} is big, and even
\Huge when {\julia} is huge.}

\end{document}

Answer 2

here is an absolute kludge. the amounts of kern may need to be adjusted depending on the size used for setting it.

\documentclass[12pt]{article}
\begin{document}
\large
\thispagestyle{empty}
jul\.\i\raisebox{.4ex}{\kern-.1em\.{}\kern-.2em}\.a
\end{document}

(from the verbal description, it sounded like you were describing the "hungarian umlaut", but that's not what your graphic shows. i've tried to match the graphic.)

here's another try, with three dots in a triangle, and an unadorned "julia" for comparison. again, full code, and caveat that the amount of kerning really is size-dependent.

\documentclass[12pt]{article}
\usepackage{graphicx}
\begin{document}
\huge
\thispagestyle{empty}
\scalebox{2}{julia}

\scalebox{2}{%
\leavevmode\rlap{julia}%
jul\.\i\raisebox{.4ex}{\kern-.15em\.{}\kern-.125em}\.{\kern-.27em}a}

\end{document}

Answer 3

Maybe simply:

\documentclass{article}

\begin{document}

\huge
Jul${\textrm{\i}}\dot{\ddot{}}$a

\end{document}

Answer 4

\documentclass{article}
\usepackage{amssymb}
\begin{document}
Jul\i\raisebox{.55em}
{\kern-.2em \tiny\ensuremath{\therefore}}\kern-.3em a
\end{document}

One more:

\documentclass{article}
\begin{document}
Julia, Juli\kern-.85em\raisebox{-.01em}{
\r{ }\kern-.6em\raisebox{.2em}{\r{ }}\kern-.6em\r{ }
}\kern-.9em \ae 
\end{document}

Answer 5

I tried a combination of \makebox and \raisebox:

juli\makebox[0pt][c]{\raisebox{0.5ex}{\.{}}}\.a

This is quite similar to barbara beeton's answer but uses a zero-width \makebox instead of \kerning.

EDIT: However, having looked at the OP's source I've decided it's a bit ugly; the dot above the a is too close far from dot between the i and the a. \kerning seems to be a better solution, IMHO.

I also looked into using the \therefore command from amssymb but it was broadly unworkable - the symbol has too much space in normalsize but the dots are weirdly small in tiny or scriptsize.