I can't get to the root of this problem: I need the second root to be the same height as the first one

$\sqrt{F} \: \sqrt{F_{x_x}}$

I know I can use \vphantom, but I don't know how.

  • Just add \vphantom{F_{x_x}} to the first square root: \sqrt{F\vphantom{F_{x_x}}}. – egreg Jun 27 '13 at 15:55
  • Thanks for your reply. But what if I want to make the second root "smaller" (small as the first root)? – user32680 Jun 27 '13 at 15:58
  • 4
    @user32680 With amsmath loaded you can do $\sqrt{F} \: \sqrt{\smash[b]{F_{x_x}}}$. – Qrrbrbirlbel Jun 27 '13 at 16:03
  • -1 for the abysmal pun. ... ok, just kidding. – Christian Jun 27 '13 at 16:38

Aligning square roots in the same formula requires some work if the symbols under the square root are not uniform in height and depth.

You can either add a phantom to the first square root or smash the bottom of the second one:



$\sqrt{F} + \sqrt{F_{x_x}}$  % original


$\sqrt{F\vphantom{F_{x_x}}} + \sqrt{F_{x_x}}$ % phantom


$\sqrt{F} + \sqrt{\smash[b]{F_{x_x}}}$ % smash


enter image description here

| improve this answer | |

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.