How can I draw a plane with equation $- \sqrt{3} x+y=0 $ in space (with tikz)?


You cannot simply use rectangle, which will not produce the expected output. But you can draw the plane "manually" like so:

enter image description here




    \draw[thick,->] (0,0,0) -- (1,0,0) node[anchor=north east]{$x$};
    \draw[thin] (0,0,0) -- ({1.2*\x},{sqrt(3)*1.2*\x},0) node[below] {$y=\sqrt{3}x$};
    ]          (0,0,0)
            -- (\x,{sqrt(3)*\x},0)
            -- (\x,{sqrt(3)*\x},1)
            -- (0,0,1)
            -- cycle;
    \draw[thick,->] (0,0,0) -- (0,1,0) node[anchor=north west]{$y$};
    \draw[thick,->] (0,0,0) -- (0,0,1) node[anchor=south]{$z$};


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.