How to shift in tikz scope relatively to an object + offset?

How do you shift (0,0) to something like: (MYBOX.west)++(0.1,0)?

Here is a MnWE:

\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{positioning, calc}

\begin{document}
\begin{tikzpicture}
\node[rectangle, draw] at (0,0) (MYBOX) {Something};
\begin{scope}[shift={$(MYBOX.east) + (0.1,0)$}]
\draw[black] (0,0) -- ++(0, -1);
\end{scope}
\end{tikzpicture}
\end{document}

• Do you need a special tikzlibrary for using $? – remus Sep 9 '13 at 12:12 • Of course :) I still get this error: ! Package tikz Error: Cannot parse this coordinate. – remus Sep 9 '13 at 12:16 • Sure. Just a sec. I'm using TikzEdt for building the figure. Let ma reconstruct the preamble. – remus Sep 9 '13 at 12:18 • You can do shift=(MYBOX.east), shift={(.1,0)}. Though be aware, that shift does not shift the origin to the specified point but the whole coordinate system about that vector. – Qrrbrbirlbel Sep 9 '13 at 12:55 1 Answer You can use syntax shift={($(MYBOX.west)+(0.1,0)$)} (which requires loading the calc library using \usetikzlibrary{calc}) for this: \documentclass{article} \usepackage{tikz} \usetikzlibrary{positioning, calc} \begin{document} \begin{tikzpicture} \node[rectangle, draw] at (0,0) (MYBOX) {Something}; \begin{scope}[shift={($(MYBOX.east) + (0.1,0)\$)}]
\draw[black] (0,0) -- ++(0, -1);
\end{scope}
\end{tikzpicture}
\end{document}