3

For example I have this table:

\begin{longtable}[c]{ p{1.0in} p{1.5in} p{2.0in} p{2.5in} }
   \multicolumn{3}{l}{ Partner } & \hfill Total \\ 
\end{longtable}

But the result is that the 'Partner' part will adjust depending on the length of the partner name. The total width should be fixed to 4.5 inches(1.0 + 1.5 + 2.0).

4

In the second argument of \multicolumn you can use a p{...} column type of the desired width. Since you need to take into account the padding for the columns (the space between the borders of the columns and their contents), the right width is 4.5in+4\tabcolsep:

\documentclass{book}
\usepackage{longtable}

\begin{document}

\begin{longtable}[c]{p{1.0in}p{1.5in}p{2.0in}p{2.5in}}
   \multicolumn{3}{p{\dimexpr4.5in+4\tabcolsep\relax}}{Partner} & \hfill Total \\
\end{longtable}

\end{document}

It's easy to give a general expression:

Let's say the multicolumn will span k columns, having format p{w1}, p{w2},...,p{wk} (here, w1,w2,...,wk are the lengths for each column); then you need to use w1+w2+...+wk+2(k-1)\tabcolsep as the width of the \multicolumn.

| improve this answer | |
  • What's the use of "+4" part in p{\dimexpr4.5in+4\tabcolsep\relax}? – eggshot Sep 10 '13 at 2:52
  • @eggshot \dimexpr4.5in+4\tabcolsep\relax evaluates to 4.5in plus 4 times \tabcolsep – Gonzalo Medina Sep 10 '13 at 2:54

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