My paper contains the following PSTricks picture. It displays a square on the left, and two squares on the right - top and bottom. It describes a process where the square on the left can be in either one of two states - either the top-right or the bottom-right state:
\begin{pspicture}(45,90)
\psframe[fillstyle=solid,fillcolor=green!20](0,20)(30,50)
\rput(15,35){V=3}
\psline{->}(35,25)(45,15)
\psline{->}(35,45)(45,55)
\end{pspicture}
\begin{pspicture}(45,90)
\psframe[fillstyle=solid,fillcolor=green!20](0,40)(30,70)
\psline[linecolor=black,linestyle=dotted](15,40)(15,70)
\rput{90}(7,55){V>2}
\rput{90}(22,55){V<1}
\psline{->}(35,55)(45,55)
\psframe[fillstyle=solid,fillcolor=green!20](0,0)(30,30)
\psline[linecolor=black,linestyle=dashed](15,0)(15,30)
\rput{90}(7,15){1$\leq$V$\leq$2}
\rput{90}(22,15){1$\leq$V$\leq$2}
\end{pspicture}
It is important that the three squares are identical (they represent the same square), so, I want them to also look identical in the PSTricks code. However, in order to arrange them vertically, I had to change their coordinates, so the left square is "(0,20)(30,50)", the top-right is "(0,40)(30,70)", and the bottom right is "(0,0)(30,30)".
Is there a way to insert a vertical shift, such that, I can just copy an existing psframe, add a shift, and it will be shifted correctly?
(I hope I made myself clear)