How can I mimic Griffiths' electrodynamics textbook?

This is such a beautiful textbook; very dear to me. I think it has a great font - which I know is Times New Roman. But somehow, I can't even get close to it. One of the main obstacles is making the font thicker somehow. Anyways, here is a sample page. If anyone can translate it into TeX, I'd be impressed.

P.S. The main issue is to somehow make the Times New Roman font a little thicker. Here is my attempt - is there any way to make this look a little less corny?:

• Welcome to TeX.SE! Please also add the code you've written to create the excerpt you've posted. Useful answers to font-related questions will depend importantly on features such as the font family (or families) you're using.
– Mico
Oct 28 '13 at 5:53
• 'Corny' is somewhat subjective and not something I normally use to describe the physically appearance of most things. Can you be a little more specific? If you use fontspec, you can tweak the 'weight' of your fonts pretty easily....
– jon
Oct 28 '13 at 5:54
• You can try by loading packages providing native support for times in math, i.e., newtx font (newtxtext anf newtxmath). Oct 28 '13 at 5:55
• I gotta go to bed now - this post will be revisited.
– Dave
Oct 28 '13 at 5:55
• Wait - what do you mean, jon, by font spec?
– Dave
Oct 28 '13 at 5:55

Source

\documentclass{article}
\usepackage{amsmath}
%%% Uncomment one at a time
\usepackage{newtxtext,newtxmath}
%\usepackage{tgtermes}\usepackage[lite]{mtpro2}
%\usepackage{stix}
%\usepackage{mathptmx}

\newcommand{\vect}[1]{\mathbf{#1}}

\begin{document}
\renewcommand\thesection{9.\arabic{section}}
\setcounter{section}{1}
\renewcommand\theequation{9.\arabic{equation}}
\setcounter{equation}{39}

\section{Electromagnetic Waves in Vacuum}

\subsection{The Wave Equation for $\vect{E}$ and $\vect{B}$}

In regions of space where there is no charge or current,
\left. \begin{alignedat}{4} &\text{(i)}\quad & \nabla\cdot\vect{E}&=0,\qquad &&\text{(ii)}\quad & \nabla\times\vect{E}&=-\frac{\partial\vect{B}}{\partial t}, \quad\\ &\text{(iii)}\quad & \nabla\cdot\vect{B}&=0,\qquad &&\text{(iv)}\quad & \nabla\times\vect{B}&=\mu_0\epsilon_0\frac{\partial\vect{E}}{\partial t}. \quad \end{alignedat} \right\rbrace
They constitute a set of coupled, first-order, partial differential equations
for $\vect{E}$ and $\vect{B}$. They can be \emph{de}coupled by applying the
curl to (iii)~and~(iv):
\begin{align*}
\nabla\times(\nabla\times\vect{E}) &=
\nabla(\nabla\cdot\vect{E})-\nabla^2\cdot\vect{E}=
\nabla\times\left(-\frac{\partial\vect{B}}{\partial t}\right)
\\[1ex]
&=
-\frac{\partial}{\partial t}(\nabla\times\vect{B})=
-\mu_0\epsilon_0\frac{\partial^2\vect{E}}{\partial t^2},
\\[2ex]
\nabla\times(\nabla\times\vect{B}) &=
\nabla(\nabla\cdot\vect{B})-\nabla^2\cdot\vect{B}=
\nabla\times\left(\mu_0\epsilon_0\frac{\partial\vect{E}}{\partial t}\right)
\\[1ex]
&=
\mu_0\epsilon_0\frac{\partial}{\partial t}(\nabla\times\vect{E})=
-\mu_0\epsilon_0\frac{\partial^2\vect{B}}{\partial t^2}.
\end{align*}
\end{document}

• I think that the mtpro2, which is the exact answer, is wrong (I think it's the same as the newtx). Oct 29 '13 at 9:40
• @Manuel You're right; I must have grabbed the wrong picture. The difference in the rendering of \partial is evident. Fixed. Oct 29 '13 at 10:00
• @Marienplatz Indeed! mtpro2 can be downloaded from pctex.com, while stix` must be manually installed from CTAN. Oct 29 '13 at 10:27
• As the nabla is a vector, should it be in bold? Oct 29 '13 at 10:50
• @Marienplatz The boldness of nabla is a stylistic choice; for me it is not a vector: I'm a mathematician, you know. ;-) Oct 29 '13 at 11:37