Angles in Chemfig

Question

I want to draw this formula using chemfig:

This is what I've got so far:

\chemfig{Cu^+(-[:180]N**6(-**6(------)--(-OOC-)---))(-[1]N)(-[5]N)(-[7]N)}

I don't get the angle from N to Cu+ right. I tried to rotate parts of the formula, but there is always at least one angle that does not fit.

Any idea?

Answer 1

Yes, I have an idea:

\documentclass{article}
\usepackage{chemfig}
\begin{document}
\definesubmol\cc{**6(---!\ff-!\ee--)}
\definesubmol\dd{**6(-!\ee--!\ff---)}
\definesubmol\ee{**6(-----)}
\definesubmol\ff[(-^{-}OOC)]{(-COO^{-})}
\chemfig{Cu^+(-[1]N([0,.5]!\cc))(-[3]N([:180,.5]!\dd))(-[5]N([:180,.5]!\cc))(-[7]N([:0,.5]!\dd))}
\end{document}

Answer 2

The following code is similar to what unbonpetit wrote. The term .5 in [0,.5] and [180,.5] is chosen such that the aromatic cycles do not get too big.

\documentclass{standalone}
\usepackage{chemfig}
\begin{document}
\chemfig{Cu^+
(-[:+ 45]N([0,.5]**6(---(-COO^{-})-**6(------)--)))
(-[:+135]N([180,.5]**6(-**6(------)--(-^{-}OOC)---)))
(-[:+225]N([180,.5]**6(---(-^{-}OOC)-**6(------)--)))
(-[:+315]N([0,.5]**6(-**6(------)--(-COO^{-})---)))}
\end{document}