# How to draw two opposite arrows on the same curve?

How can I draw opposite arrows on the same curve? The following image shows my aim. • an you show us what you got so far in the form of a minimal working example? – Johannes_B Jan 22 '14 at 8:00
• I am still very new to this. I don't know how to do that at all. I just downloaded pgfplots package today. – Ruzayqat Jan 22 '14 at 8:09
• Have a look at its manual, there is a good tutorial. – Johannes_B Jan 22 '14 at 8:10
• I did. But I couldn't find anything related to what I am asking for. Two arrows on the same curve (the curve may have an equation xy-coordinates) – Ruzayqat Jan 22 '14 at 8:11

The right way to go here is with the library decorations.markings and to define a style that places both arrows and labels.

This is a possibility (some ideas taken from How to make a figure with moving arrows?):

\documentclass[12pt,a4paper]{article}
\usepackage{tikz}

\usetikzlibrary{decorations.markings,arrows} % arrows for *-* tips

\pgfkeys{/tikz/.cd,
arrow color/.store in=\arrowcolor,
arrow color=black,
arrow tip/.store in=\arrowtip,
arrow tip=to,
label 1/.store in=\labone,
label 1={},
label 2/.store in=\labtwo,
label 2={},
}

\tikzset{double arrow/.style args={in #1 and #2}{
postaction=decorate,
decoration={
markings,
mark=at position #2 with {
\arrow[\arrowcolor,arrows options]{\arrowtip};
\node[labels options]{\labtwo};
},
mark=at position #1 with {
\arrowreversed[\arrowcolor,arrows options]{\arrowtip};}
\node[labels options]{\labone};
}
},
arrows options/.style={
thick
},
labels options/.style={
above=0.1cm
}
}

\begin{document}
\begin{tikzpicture}
\draw[-stealth, very thick](0,0)--(6,0) node[below]{$x$};
\draw[-stealth, very thick](0,0)--(0,5) node[left]{$y$};

\draw[thick,
arrow tip={stealth},
double arrow=in 0.2 and 0.8, % places
label 1={$-C$},
label 2={$C$},
*-*, % tips at both sides of the path
]
(1,1) node[below] {$z_1$}
.. controls (3,3) and (5,3) ..
(5,3) node[below] {$z_2$};

\end{tikzpicture}
\end{document}


The result: • When I performed it actually I got a picture like this but without the two endpoints marks. Any suggestions? – Ruzayqat Jan 22 '14 at 8:45
• Sorry, my fault :). I updated the first version, but forgetting to add the arrows library and tips. I'll edit the answer. – Claudio Fiandrino Jan 22 '14 at 8:47

Another version with tikz v3:

\documentclass[tikz,border=10pt]{standalone}
\usetikzlibrary{decorations.markings,arrows.meta}

\tikzset{
->-/.style={decoration={
markings,
mark=at position .85 with {\arrow{Latex}}},postaction={decorate}},
-<-/.style={decoration={
markings,
mark=at position .15 with {\arrow{Latex[reversed]}}},postaction={decorate}},
}
\begin{document}
\begin{tikzpicture}
\draw (-1,0) -- node[pos=0.1,below] {$O$} (6,0)node[pos=0.98,below] {$x$};
\draw (0,-1) -- (0,6)node[pos=0.98,left] {$y$};

\node[inner sep=2pt,circle,fill=black,label={below:$z_{1}$}] at  (1,2) (a) {} ;
\node[inner sep=2pt,circle,fill=black,label={below:$z_{2}$}] at  (5,3) (b) {} ;
\draw (a) edge[in=180,out=30,->-,-<-] node[pos=0.1,above]{$-C$} node[pos=0.85,above]{$C$} (b) ;
\end{tikzpicture}
\end{document} With PSTricks just for fun.

\documentclass[pstricks,border=12pt,12pt]{standalone}
\psaxes[labels=none,ticks=none](0,0)(-1,-1)(7,4)[$x$,-90][$y$,180]
\pcarc[arcangle=20](z_1)(z_2)^{$C$}
\pcarc[arcangle=-20](z_2)(z_1)_{$-C$} 