LaTeX command for double lower index summation [duplicate]

I would like to know what is the latex command to include a double lower index using sigma notation (i.e: second index lies underneath the first index)?

I tried typing:

\displaystyle\sum_{m,n=-\infty, \; (m,n)\neq (0,0)}^{\infty}
\left[
\frac{1}{(z-2 m\omega_{1} - 2 n\omega_{2})^{2}}
-\frac{1}{   4(m\omega_{1} +   n\omega_{2})^{2}}
\right]


I would appreciate the assistance. Thanks

• Welcome to TeX.SX! Could you please add some context? What's \dsy, for instance? Feb 10, 2014 at 14:39
• Hi Greg. \dsy means displaystyle for the sigma sign Feb 10, 2014 at 14:42
• You don't need \displaystyle; if your formula is inline, use \sum\limits (or simply \sum, which is better). Feb 10, 2014 at 14:46

The \substack command from the amsmath package can do what you are after:

\documentclass{article}

\usepackage{amsmath}

\begin{document}
\begin{equation*}
\sum_{\substack{m,n=-\infty,\\(m,n)\neq (0,0)}}^{\infty}\left[\frac{1}{(z-2 m\omega_{1}-2 n\omega_{2})^{2}}-\frac{1}{4(m\omega_{1}+n\omega_{2})^{2}}\right]
\end{equation*}
\end{document}


Or without the comma, since the next condition is on a new line:

\documentclass{article}

\usepackage{amsmath}

\begin{document}
\begin{equation*}
\sum_{\substack{m,n=-\infty\\(m,n)\neq (0,0)}}^{\infty}\left[\frac{1}{(z-2 m\omega_{1}-2 n\omega_{2})^{2}}-\frac{1}{4(m\omega_{1}+n\omega_{2})^{2}}\right]
\end{equation*}
\end{document}


• Thank you very much for all your comments and i appreciate the assistance! Feb 10, 2014 at 15:01

Try using substack:

\usepackage{amsmath}

...

$$\prod_{\substack{ 1 \le i \le n \\ 1 \le j \le m} } M_{i,j}$$


This example is taken from the Latex Wikibook.