I'm looking to reproduce a diagram using the tikz package from a paper in JASA: Moodie et al 2009 104(485):155-65. This is the figure:

enter image description here

The nodes and arrows don't seem too difficult to generate. But I'm stumped on how to put a timescale axis, and space the nodes so that they align with it. So, to make this question relevant to a more general audience, how does one put an x-axis on the bottom of a tikz diagram, and align the nodes with elements on the axis?

Here's a starting example for time-points 0 and 1:

\begin{tikzpicture}[line width=0.05cm]
\node [circle,draw] (h1) at (0,2) {$h$};
\node [circle,draw] (h2) at (2,2) {$h$};

\node [circle,draw] (b1) at (1.5,4) {$b$};

\begin{scope}[line width=.1cm,shorten >= 5pt, shorten <= 5pt]
\draw[->] (h1) -- (h2);
\draw[->] (h1) -- (b1);
\draw[->] (b1) -- (h2);

\draw[help lines] (0,0) grid (5,5) ;

I'm looking for what I can add to this code to get the time-axis (lines, tick marks, numbers, and title).

  • you can put the nodes on a grid. Or you could fake the timescale as nodes below the lower nodes.
    – papabravo
    Feb 14, 2014 at 14:39

2 Answers 2


Tikz knows quite a lot about repetitive jobs. Here is a shorter version of Nicos answer:

%%plot the wt nodes and timeline ticks
\foreach \x in {0,1,2,3,6,9,12} { 
  \draw (\x ,0) node[anchor=north] {\x} -- (\x,0.1);
  \node[draw,circle] (wt\x) at (\x,1) {wt};
%%plot the bt nodes and most edges
%%alternative for older tikz versions:
%\foreach[remember =\x as \lastx] \x in {1,2,3,6,9,12} {
%%works for me with current version (3.0.0)
\foreach[remember =\x as \lastx (initially 0)] \x in {1,2,3,6,9,12} {
  \node[draw,circle] (bf\lastx) at (0.5+\lastx,2) {bf};
  \path[->] (wt\lastx) edge (wt\x);
  \path[->] (wt\lastx) edge (bf\lastx);
  \path[->] (bf\lastx) edge (wt\x);
%%plot the missing edges
\foreach[remember =\x as \lastx (initially 0)] \x in {1,2,3,6,9} {
  \path[->] (bf\lastx) edge (bf\x);
\draw[->] (-.5,0) -- (12.5,0);

Edit: Added alternative version according to this.

The Result :


  • Does it compile?
    – ajeh
    Feb 14, 2014 at 15:50
  • It does for me. Maybe the remember key is new in tikz 3.0? I just learnt about it...
    – papabravo
    Feb 14, 2014 at 15:56
  • @papabravo, your approach is enticing, but there seems to be a mistake (typo?) in your code that I can't find. There is only one node for bf, and the arrows aren't quite working out. Feb 14, 2014 at 16:00
  • I should definitely learn this kind of stuff.
    – Nico
    Feb 14, 2014 at 16:10
  • Added a version that should work with the 2.1 version. Haven't tested it because I don't want to mess with my installation (I'm happy it's running...)
    – papabravo
    Feb 14, 2014 at 16:15

For something as simple as this I would KISS.

If you are a newbie like me, the simpler the better.



[node distance=4mm and 1.75mm, bubbles/.style={draw,circle, minimum size=2em}]
% Bottom
\node[bubbles] (wt0) at (0, 0) {wt};
\node[bubbles] (wt1) at (1, 0) {wt};
\node[bubbles] (wt2) at (2, 0) {wt};
\node[bubbles] (wt3) at (3, 0) {wt};
\node[bubbles] (wt6) at (6, 0) {wt};
\node[bubbles] (wt9) at (9, 0) {wt};
\node[bubbles] (wt12) at (12, 0) {wt};

% Top
\node[bubbles] (bf0) [above right=of wt0] {bf};
\node[bubbles] (bf1) [above right=of wt1] {bf};
\node[bubbles] (bf2) [above right=of wt2] {bf};
\node[bubbles] (bf3) [above right=of wt3] {bf};
\node[bubbles] (bf6) [above right=of wt6] {bf};
\node[bubbles] (bf9) [above right=of wt9] {bf};

% Arrows
\draw [-latex,thick](wt0) -- (bf0);
\draw [-latex,thick](wt0) -- (wt1);
% And so on

% Timeline
\node at (0, -1) {0};
\node at (1, -1) {1};
\node at (2, -1) {2};
\node at (3, -1) {3};
\node at (6, -1) {6};
\node at (9, -1) {9};
\node at (12, -1) {12};

enter image description here


  • Put the bottom nodes at the position you want. You can use months number like I did.
  • Put the top nodes relative to the bottom nodes (that's what it looks like in the picture you put)
  • Arrows are pretty straightforward.
  • Timeline: The nodes are in the same place as the bottom nodes.

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .