# Delta-equal to symbol [duplicate]

How do you write the equal-to symbol with delta on top ("delta-equal to")? One similar to http://www.decodeunicode.org/de/u+225c. Are special packages required for that? It is supposed to be used for definition of equalities, similar to :=.

• Try $\overset{\Delta}{=}$. Mar 5 '14 at 14:57
• \triangleq, after \usepackage{amssymb} Mar 5 '14 at 15:06

• actually, \usepackage{amssymb} is needed for this. while amsmath loads amsfonts, not all the symbols are "named" unless amssymb is loaded explicitly. Mar 5 '14 at 15:22

EDITED to ensure rendering of the = in math mode. For more flexibility in the vertical placement, than the \overset (which requires amsmath package), you could try

\documentclass{article}
\usepackage{stackengine}
\def\delequal{\mathrel{\ensurestackMath{\stackon[1pt]{=}{\scriptstyle\Delta}}}}
\begin{document}
$a \delequal b$
\end{document}

The optional argument to \stackon specifies the vertical gap between symbols. If you wanted the delta smaller, you could add \scriptscriptstyle in place of the \scriptstyle:

For comparison, here is $a \overset{\Delta}{=} b$. Note the vertical offset is significantly larger than what I proposed.

• Maybe illustrate the \overset{}{} just to compare. Mar 5 '14 at 15:04
• Thanks for the exhaustive answer, I really appreciate it, I'll keep this in mind when creating other stacked symbol monstrosities, but today the simpler \triangleq saves the day (and my latex refuses to download stackengine.sty for some reason). Mar 5 '14 at 15:12
• Understood. Best wishes. FYI, the package is at ctan.org/pkg/stackengine Mar 5 '14 at 15:13
• I needed $=$, not =, as in \def\delequal{\mathrel{\stackon[1pt]{$=$}{$\scriptscriptstyle\Delta$}}} to get a correct result, since the first argument of \stackon appears to be rendered in text mode just like the second. At least, with = the output looks wrong and different. Mar 24 '16 at 9:32
• @Blaisorblade Thank you for pointing that out. For some fonts, there is no difference I think, but to guarantee math mode rendering, I have updated the answer. Mar 24 '16 at 10:06