2

I've been working on the following table:

 \vspace{1mm}
 \begin{table}[hb]
    \begin{tabular}{cc|c|c|c|c|l}
    \cline{1-6}
    & & \multicolumn{2}{ |c| }{\bf Annotator B} \\ \cline{3-4}
    & & Yes & No \\ \cline{1-5}
    \multicolumn{1}{ |c| }{\multirow{2}{*}{\bf Annotator A} } & 
    \multicolumn{1}{ |c| }{Yes} & $P_{1.} . P_{.1}$  & $P_{1.} . P_{.2}$  & $P_{1.}$   \\ \cline{2-5}
    \multicolumn{1}{ |c  }{}                        &
    \multicolumn{1}{ |c| }{No} &  $P_{2.} . P_{.1}$  & $P_{2.} . P_{.2}$  & $P_{2.}$    \\ \cline{2-5}
    \multicolumn{1}{ |c  }{}                        &
    \multicolumn{1}{ |c| }{} &  $P_{.1}$ & $P_{.2}$   \\ \cline{3-4}
\end{tabular}

It's currently producing this table:

enter image description here

I obviously want the cells with annotator a and b to have full borders but I can't seem to get it to work. I've tried inserting \ \hline and modifying my cline's and no luck.

0

This seems to work:

 \begin{table}[hb]
    \begin{tabular}{cc|c|c|c|c|l}
        \cline{3-4}
        & & \multicolumn{2}{ |c| }{\bf Annotator B} \\ \cline{3-4}
        & & Yes & No \\ \cline{1-5}
        \multicolumn{1}{ |c| }{\multirow{2}{*}{\bf Annotator A} } & 
        \multicolumn{1}{ |c| }{Yes} & $P_{1.} . P_{.1}$  & $P_{1.} . P_{.2}$  & $P_{1.}$   \\ \cline{2-5}
         \multicolumn{1}{ |c  }{}                        &
         \multicolumn{1}{ |c| }{No} &  $P_{2.} . P_{.1}$  & $P_{2.} . P_{.2}$  & $P_{2.}$    
         \\ \cline{2-5}
         \multicolumn{1}{ |c  }{}                        &
         \multicolumn{1}{ |c| }{} &  $P_{.1}$ & $P_{.2}$   
         \\ \cline{1-1}\cline{3-4}
    \end{tabular}
\end{table}

enter image description here

The problems were the first and last \cline.

EDIT. As asked in the comment:

\begin{tabular}{cc|c|c|c|c|l}
\cline{3-4}
& & \multicolumn{2}{ |c| }{\bf Annotator B} 
\\ \cline{3-4}
& & Yes & No \\ \cline{1-5}
\multicolumn{1}{ |c| }{\multirow{2}{*}{\bf Annotator A} } & 
\multicolumn{1}{ |c| }{Yes} & $P_{1.} . P_{.1}$  & $P_{1.} . P_{.2}$  & $P_{1.}$   
\\ \cline{2-5}
\multicolumn{1}{ |c  }{}                        &
\multicolumn{1}{ |c| }{No} &  $P_{2.} . P_{.1}$  & $P_{2.} . P_{.2}$  & $P_{2.}$    
\\ \cline{1-5}
\multicolumn{1}{ c  }{}                        &
\multicolumn{1}{ c| }{} &  $P_{.1}$ & $P_{.2}$   \\ \cline{3-4}
\end{tabular}

enter image description here

  • how would you modify this so that the bottom of the cell containing annotator a would finish the same level as the bottom of the no cell? – user47467 Mar 7 '14 at 10:33
  • @user47467 See my edited answer. – Franck Pastor Mar 7 '14 at 15:07

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