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I've read the circuitikz documentation already and there is not such a symbol (not at least in the documentation) comparable with the white/empty arrow on the upper right corner of the circuit (marked as voltage V0). Is there a way of doing so? I am not looking for a current arrow. Impedance circuit

EDIT:

Here is the circuit code.

\usepackage{circuitikz}
\begin{center}
\begin{circuitikz}[american]
\draw (2,0)--(0,0) node[ground]{} to[sV, v=\textit{vi=4Vpp}] (0,2) to[R, l=\textit{r}$_0$\textit{=50$\Omega$}](2,2) to[open] (2,0)--(5.5,0);
\draw (2,2) to[short, *-] (2,1.3) to[short] (2.75,1.3) to[short] (2.75,1.65) to[short, i=$ $] (2.75,2);
\draw (2,2) to[R, l^=$10K\Omega$] (3.5,2) to[short] (4,2);
\draw (3.5,2) -- (4.5,2) to[short, *-*] (5.5,2) to[short] (5.8,2) to[short, i=$ $] (6,2);
\draw (4.5,2) to[R, l_=$10K\Omega$] (4.5,0);
\draw (5.5,2) to[R, l=$5K\Omega$] (5.5,0);
\draw (4.25,1.6) -- (4.25,2.2) to[short] (4.3,2.2) to[short, i=$Z_A$] (4.5,2.2);
\draw (4,2) to[short, -o] (4,2.3);
\draw (4.4,2.5)to[open, l=$A$] (4.4,2.7);
\end{circuitikz}
\captionof{figure}{\small Impedance circuit.}
\end{center}
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  • You can simply add an arrow with that head and a node at the end. It will be better if you post the code you have tried already, starting from \documentclass{}... and ending at \end{document} for us to be specific. :)
    – user11232
    Commented Mar 12, 2014 at 4:32
  • @HarishKumar I added the circuit code, I can't find useful to add all the document class and everything.
    – Hans
    Commented Mar 12, 2014 at 4:44
  • 1
    @Hans: however, we always ask to post complete minimal working examples rather than code snippets because this really helps people to answer you. Maybe from your point of view is useless, however consider the extra effort people does in adding the correct packages, libraries and perhaps custom commands. Commented Mar 12, 2014 at 6:14

1 Answer 1

6

A work around:

\documentclass{article}
\usepackage{circuitikz,caption}
\begin{document}
\begin{center}
\begin{circuitikz}[american]
\draw (2,0)--(0,0) node[ground]{} to[sV, v=\textit{vi=4Vpp}] (0,2) to[R, l=\textit{r}$_0$\textit{=50$\Omega$}](2,2) to[open] (2,0)--(5.5,0);
\draw (2,2) to[short, *-] (2,1.3) to[short] (2.75,1.3) to[short] (2.75,1.65) to[short, i=$ $] (2.75,2);
\draw (2,2) to[R, l^=$10K\Omega$] (3.5,2) to[short] (4,2);
\draw (3.5,2) -- (4.5,2) to[short, *-*] (5.5,2) to[short] (5.8,2);% to[short, i=$$] (6,2);
 \draw[-open triangle 45] (5.8,2)--(7,2)node[right] {V0};
\draw (4.5,2) to[R, l_=$10K\Omega$] (4.5,0);
\draw (5.5,2) to[R, l=$5K\Omega$] (5.5,0);
\draw (4.25,1.6) -- (4.25,2.2) to[short] (4.3,2.2) to[short, i=$Z_A$] (4.5,2.2);
\draw (4,2) to[short, -o] (4,2.3);
\draw (4.4,2.5)to[open, l=$A$] (4.4,2.7);
\end{circuitikz}
\captionof{figure}{\small Impedance circuit.}
\end{center}
\end{document}

enter image description here

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  • As an additional remark concerning units: There is package siunitx taking care of almost everything.
    – Johannes_B
    Commented Mar 12, 2014 at 6:56

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