Including +/- signs to battery in Circuitikz

Question

I'm attempting to draw a battery (using the battery1 component) that includes positive and negative signs at the appropriate ends. A previous question that was answered here (using version 2.4) shows exactly what I mean:

Only, of course, I want to be using a battery1 symbol instead. So, I have my code as follows:

\usepackage[americanvoltages,fulldiodes,siunitx]{circuitikz}
\begin{document}
\begin{circuitikz}
    \draw (0,0) to [battery1=\SI{9}{V}] (3,0)
                to [pC,v=$v_C$] (6,0);
\end{circuitikz}
\end{document}

And I end up with this:

Notice the lack of +/- signs (I know how circuits work so I don't need to be actually shown these signs, but for the sake of copying my class notes diagrams I want these signs to be included in my latex diagram).

In either case, I think it may have something to do with the version of Circuitikz I'm using because I'm using the latest version (I believe, 0.3.0) but in the previous question linked above, they were using 2.4 and it worked out for them.

I would really like to find a way to add +/- without having to manually add it with Tikz or something, i.e. just have it naturally part of the component without having to add nodes or extra Tikz code etc. If that's not possible, then I'll have to settle for that as a last result.

Thank you for your help!

EDIT: I should also mention that I've tried using battery1, v=$9V$ instead of battery1=\SI{9}{V} and to no avail (the +/- signs still don't show up).

Answer 1

A solution meeting the stated requirements: the + and - signs are placed natively without extra packages nor manually adding them. This implies redefining \pgf@circ@drawvoltagegenerator as defined in pgfcircvoltage.sty (the only thing that has to be done is to comment out a conditional that prevents the signs from appearing):

\documentclass{article}
\usepackage[americanvoltages,fulldiodes,siunitx]{circuitikz}
\usepackage{ifthen}

\makeatletter
  \def\pgf@circ@drawvoltagegenerator{
    \ifpgf@circuit@bipole@voltage@below
        coordinate (pgfcirc@Vcont1) at ($(\ctikzvalof{bipole/name}.center) ! \ctikzvalof{voltage/bump a} ! (\ctikzvalof{bipole/name}.-120)$)
        coordinate (pgfcirc@Vcont2) at ($(\ctikzvalof{bipole/name}.center) ! \ctikzvalof{voltage/bump a} ! (\ctikzvalof{bipole/name}.-60)$)
    \else
        coordinate (pgfcirc@Vcont1) at ($ (\ctikzvalof{bipole/name}.center) ! \ctikzvalof{voltage/bump a} ! (\ctikzvalof{bipole/name}.120)$)
        coordinate (pgfcirc@Vcont2) at ($ (\ctikzvalof{bipole/name}.center) ! \ctikzvalof{voltage/bump a} ! (\ctikzvalof{bipole/name}.60)$)
    \fi

    \ifpgf@circuit@europeanvoltage
        \ifpgf@circuit@bipole@voltage@backward
            (pgfcirc@Vcont2)  -- node[currarrow, sloped,  allow upside down, pos=1] {} (pgfcirc@Vcont1)
        \else
            (pgfcirc@Vcont1)  -- node[currarrow, sloped,  allow upside down, pos=1] {} (pgfcirc@Vcont2)
        \fi

    \else % american voltage

        \pgfextra{
            \edef\pgf@temp{\pgfkeysvalueof{/tikz/circuitikz/bipole/kind}}
            \def\pgf@circ@temp{battery}
            \ifx\pgf@temp\pgf@circ@temp
                \def\pgf@circ@batteria{battery}
            \else
                \edef\pgf@circ@temp{battery1}
                \ifx\pgf@temp\pgf@circ@temp
                    \edef\pgf@circ@batteria{battery}
                \else
                    \edef\pgf@circ@batteria{false}
                \fi
            \fi
            \def\pgf@circ@temp{battery1}
        }

        \ifx\pgf@temp\pgf@circ@temp % if it is a battery, must put + and -
            \ifpgf@circuit@bipole@voltage@backward
                (pgfcirc@Vcont2)  node[xshift=2pt,yshift=-6pt] {$-$}  (pgfcirc@Vcont1) node[xshift=-2pt,yshift=-6pt] {$+$}
            \else
                (pgfcirc@Vcont1)  node[xshift=-2pt,yshift=-6pt] {$-$}  (pgfcirc@Vcont2) node[xshift=2pt,yshift=-6pt] {$+$}
            \fi
        \fi

    \fi
}
\makeatother
\begin{document}
\begin{circuitikz}
    \draw (0,0) to [battery1,v>=\SI{9}{V}] (3,0)
                to [pC,v=$v_C$] (6,0) 
                to[cV, v=\SI{9}{V}] (9,0)
                ;
\end{circuitikz}

\end{document}

A remark:

I think that the missing + and - signs might be a bug in circuitikz. If one looks at the relevant code I modified:

\else % american voltage
        
        \pgfextra{
            \def\pgf@temp{\pgfkeysvalueof{/tikz/circuitikz/bipole/kind}}
            \def\pgf@circ@temp{battery}
            \ifx\pgf@temp\pgf@circ@temp
                \edef\pgf@circ@batteria{battery}
            \else
                \def\pgf@circ@temp{battery1}
                \ifx\pgf@temp\pgf@circ@temp
                    \edef\pgf@circ@batteria{battery}
                \else
                    \edef\pgf@circ@batteria{false}
                \fi
            \fi
            \edef\pgf@circ@temp{battery}
        }
        
        \ifx\pgf@circ@batteria\pgf@circ@temp % if it is a battery, must put + and -
            \ifpgf@circuit@bipole@voltage@backward
                (pgfcirc@Vcont2)  node {$-$}  (pgfcirc@Vcont1) node {$+$}
            \else
                (pgfcirc@Vcont1)  node {$-$}  (pgfcirc@Vcont2) node {$+$}
            \fi
        \fi
        
    \fi

The line

\ifx\pgf@circ@batteria\pgf@circ@temp % if it is a battery, must put + and -

suggests that the package author intended to include the + and - signs for batteries; however, the conditional above the mentioned line won't produce the expected condition since an \def was used instead of \edef here:

\def\pgf@temp{\pgfkeysvalueof{/tikz/circuitikz/bipole/kind}}

and the last conditional should be

\ifx\pgf@temppgf@circ@temp

instead of

\ifx\pgf@circ@batteria\pgf@circ@temp 

Perhaps it would be a good idea to contact the package author and ask him if this is indeed a bug or if he decided not to add the signs in all cases.

Answer 2

Just an update... (after 7 years)

\documentclass{article}
\usepackage[americanvoltages,fulldiodes,siunitx]{circuitikz}
\begin{document}
\begin{circuitikz}
\draw (0,0) to [battery1=$\,$] (3,0);
\end{circuitikz}
\end{document}

does the job.

I just typ \backslash , to have the the signs

Answer 3

Here are two possibilities. The first using subscripts, the second using stacks.

\documentclass{article}
\usepackage[americanvoltages,fulldiodes,siunitx]{circuitikz}
\usepackage{stackengine}
\parskip 1em
\begin{document}
\begin{circuitikz}
    \draw (0,0) to [battery1=$_-$\SI{9}{V}$_+$] (3,0)
                to [pC,v=$v_C$] (6,0);
\end{circuitikz}

\begin{circuitikz}
    \draw (0,0) to [battery1=\smash{\stackunder[6pt]{\SI{9}{V}}{$_-$~~~$_+$}}] (3,0)
                to [pC,v=$v_C$] (6,0);
\end{circuitikz}
\end{document}

Answer 4

Another possible solution with TiKz draw command:

\documentclass{article}

\usepackage[americanvoltages,fulldiodes,siunitx]{circuitikz}

\begin{document}
\begin{circuitikz}

  \draw (0,0) to [battery1=\SI{9}{V}] (3,0)
                to [pC,v=$v_C$] (6,0);

              \draw (1,0.3) node{$-$};
              \draw (2,0.3) node{$+$};

\end{circuitikz}
\end{document}