34

Is it possible to type a radical of a square root equation as \sqrt{} with any number inside the bracket? I looked up how to do it but there were only these answers with advanced LaTeX that I don't understand. Any help someone?

closed as unclear what you're asking by egreg, Svend Tveskæg, Malipivo, Jesse, Heiko Oberdiek Apr 17 '14 at 11:27

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

  • 1
    You can just use \surd. See How to look up a symbol or identify a math alphabet? – Werner Mar 26 '14 at 21:15
  • 2
    Welcome to TeX.SE. Yes, just make sure you are in math mode: example $\sqrt{}$, or if you want the horizontal line $\sqrt{\hphantom{99}}$, where the widthof{99} determines how wide it is. If you actually have a number just use $\sqrt{<num>}$. – Peter Grill Mar 26 '14 at 21:19
  • It's not clear what you're asking. Do you want a square root sign with nothing under it, or an nth root sign (like cube root, fourth root, etc.)? None of these require "advanced LaTeX" (first is \surd, second is \sqrt[n]{x}), so maybe you want something else? – wchargin Apr 17 '14 at 5:04
39
\documentclass[preview,border=12pt,12pt,varwidth]{standalone}% change this line to \documentclass{article} or whatever you want.

\begin{document}
\noindent
The square root of 100 is $\sqrt{100}=10$. 
\\
But the cubic root of 64 is $\sqrt[3]{64}=4$.
\end{document}

enter image description here

3

You can just use \sqrt{.........} and put what ever numbers between the brackets.

  • 2
    Welcome to TeX.SX! You're missing the $ and $ for math mode. Also, it might be helpful to make a complete minimal working example so you can show the result in your answer. – Adam Liter Apr 17 '14 at 2:58

Not the answer you're looking for? Browse other questions tagged or ask your own question.