I am wanting to draw a tetrahedron with labeled points on each corner. I attempted to edit the example of a cone that I found here: A cone with tikzpicture I have made it look partially like a tetrahedron but have not been able to get it right (let alone labeled points). This is what I’ve got so far:





 \draw[] (\RI,0)
   \foreach \x in {0,240} { --  (\x:\RI) node at (\x:\RI) (R1-\x) {} };
 \draw[dashed,thick] (R1-0.center)
   \foreach \x in {120} { --  (\x:\RI) node at (\x:\RI) (R1-\x) {} };

 \draw[thick,fill=gray!30,opacity=0.2] (\RII,0)
   \foreach \x in {0,120,240,360}
     { --  (\x:\RII) node at (\x:\RII) (R2-\x) {}};

 \foreach \x in {0,240} { \draw (R1-\x.center)--(R2-\x.center); };
 \foreach \x in {120} { \draw[dashed] (R1-\x.center)--(R2-\x.center); };


and this is what it compiles to give:

enter image description here


With help from Wikipedia and TikZ


\begin{tikzpicture}[line join = round, line cap = round]
\coordinate [label=right:A] (A) at (2,0,-2*\factor);
\coordinate [label=left:B] (B) at (-2,0,-2*\factor);
\coordinate [label=above:C] (C) at (0,2,2*\factor);
\coordinate [label=below:D] (D) at (0,-2,2*\factor);

\draw[->] (0,0) -- (3,0,0) node[right] {$x$};
\draw[->] (0,0) -- (0,3,0) node[above] {$y$};
\draw[->] (0,0) -- (0,0,3) node[below left] {$z$};
\foreach \i in {A,B,C,D}
    \draw[dashed] (0,0)--(\i);
\draw[-, fill=red!30, opacity=.5] (A)--(D)--(B)--cycle;
\draw[-, fill=green!30, opacity=.5] (A) --(D)--(C)--cycle;
\draw[-, fill=purple!30, opacity=.5] (B)--(D)--(C)--cycle;



  • Does anyone know which modifiers add nodes at the points A,B,C,D? – Relative0 Aug 7 '14 at 18:25
  • @user1922184 If your question means how letters A, B, C and D are written, the answer is label:right:A in coordinate options. If your question is not this, please rephrase it. – Ignasi Aug 8 '14 at 17:50
  • I was able to figure out the code for moving the label around, but really appreciate it. I however am having trouble finding looking for the code to put points at the corners so one at each A,B,C, and D. For example, the answer that "Don Joe" gave below has the black nodes but I am unsure how to get "\draw[fill=black] (P\i) circle (0.15em)" to work. – Relative0 Aug 10 '14 at 21:07
  • @user1922184: As Dohn Joe did it, draw them over each coordinate: \foreach \i in {A, B, C, D} \fill[black] (\i) circle(1pt); Depending where you include these lines, the circles will be (or not) covered with tetrahedron faces. – Ignasi Aug 11 '14 at 15:32
  • I am using your tetrahedron in some solutions I am creating for myself on github. Is there any way you want to be credited or cited? github repo – dustin Jan 20 '15 at 18:29

this is a hexahedral, but maybe this gives you a starting point.

\begin{tikzpicture}[x=0.65cm, y=0.65cm]

% Specify the coordinates
\coordinate (P0) at (0.0, 0.0); % 0
\coordinate (P1) at (10.0, 0.0); % 1
\coordinate (P2) at (13.0, 2.50); % 2
\coordinate (P3) at (3.0, 2.50); % 3

\coordinate (P4) at (0.0, 6.0); % 4
\coordinate (P5) at (10.0, 6.0); % 5
\coordinate (P6) at (14.0, 8.50); % 6
\coordinate (P7) at (3.0, 8.50); % 7

% draw and number the edges
\draw[line width=0.5pt] (P0) -- (P1);
\node[fill=white] (c) at ($(P0)!0.5!(P1)$) {$0 \,\rightarrow$};

\draw[line width=0.5pt] (P1) -- (P2);
\node[fill=white] (c) at ($(P1)!0.55!(P2)$) {$\overset{\nearrow}{5}$};

\draw[line width=0.5pt] (P0) -- (P4);
\node[fill=white] (c) at ($(P0)!0.5!(P4)$) {$\overset{\uparrow}{8}$};

\draw[line width=0.5pt] (P4) -- (P5);
\node[fill=white] (c) at ($(P4)!0.5!(P5)$) {$3 \,\rightarrow$};

\draw[line width=0.5pt] (P4) -- (P7);
\node[fill=white] (c) at ($(P4)!0.5!(P7)$) {$\overset{\nearrow}{7}$};

\draw[line width=0.5pt] (P5) -- (P6);
\node[fill=white] (c) at ($(P5)!0.5!(P6)$)   {$\overset{\text{\rotatebox[origin=c]{-8}{$\nearrow$}}}{6}$};

\draw[line width=0.5pt] (P7) -- (P6);
\node[fill=white] (c) at ($(P7)!0.5!(P6)$) {$2 \,\rightarrow$};

\draw[line width=0.5pt] (P1) -- (P5);
\node[fill=white] (c) at ($(P1)!0.6!(P5)$) {$\overset{\uparrow}{9}$};

\draw[line width=0.5pt] (P2) to[out=90,in=-120] (P6);
\node[fill=white,anchor=east] (c) at ($(P2)!0.5!(P6)$)     {$\overset{\text{\rotatebox[origin=c]{-10}{$\uparrow$}}}{10}$};

\draw[dashed, line width=0.5pt] (P3) -- (P0);
\node[fill=white] (c) at ($(P0)!0.65!(P3)$) {$\overset{\nearrow}{4}$};

\draw[dashed, line width=0.5pt] (P3) -- (P2);
\node[fill=white] (c) at ($(P3)!0.5!(P2)$) {$1 \,\rightarrow$};

\draw[dashed, line width=0.5pt] (P3) -- (P7);
\node[fill=white] (c) at ($(P3)!0.35!(P7)$) {$\overset{\uparrow}{11}$};

% numbering the nodes
\foreach \i in {2,3,6,7}
    \draw[fill=black] (P\i) circle (0.15em)
    node[above right,blue,font=\bfseries] {\Large \i};
\foreach \i in {0,1,4,5}
    \draw[fill=black] (P\i) circle (0.15em)
    node[below left,blue,font=\bfseries] {\Large \i};

% coordinate system
\node (x) at ($(P0)!0.15!(P1)$) {};
\node (y) at ($(P0)!0.45!(P3)$) {};
\node (z) at ($(P0)!0.35!(P4)$) {};

\draw[-latex,thick] (P0) to (x) node [below] {$x$};
\draw[-latex,thick] (P0) to (y) node [below] {$y$};
\draw[-latex,thick] (P0) to (z) node [right] {$z$};


A block

The points are labelled, so this will be rather easy to modify. Have fun. I created this image from some example from TeXample.net.

The following code creates the block as a standalone image. Works with pdflatex.





Run with xelatex


\psset{viewpoint=40 10 10 rtp2xyz,lightsrc=viewpoint,Decran=30}
\psSolid[object=tetrahedron,r=3,action=draw*,name=T,num=1 2 3]% without 0
\psSolid[object=point,definition=solidgetsommet,args=T 0,text=Top,pos=uc]% Point T0 (top)

enter image description here


How about this one.




\draw[thick, fill=gray] (0,1.5) -- (1.2,0.4) -- (0,-1) -- (0,1.5) -- (-1.6,-0.1) -- (0,-1);
\draw[thick, dashed] (1.1,0.4) -- (-1.5,-0.1) ;

\draw[thick, red] (-0.5132,0.247) -- (-2.1795,0.0633) ;
\draw[thick, red, dashed] (1.839,0.4928) -- (-0.396,0.247) ;

\fill (-1.8,-0.4) circle (0pt) node[above] {4};
\fill (0,-1.5) circle (0pt) node[above] {3};
\fill (1.3,0.4) circle (0pt) node[above] {2};
\fill (0,1.6) circle (0pt) node[above] {1};



enter image description here

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.